Bourbaki

Exercise 10, § 2

Lie Groups and Lie Algebras, IV

Let GG be a group and BB a Tits subgroup of GG. We use the notation of Exerc. 3. For s∈Ss \in S, denote by G(s)G^{(s)} the subgroup GS−{s}G_{S-\{s\}} (Exerc. 3 g)). Let II be the set of subsets of GG of the form gG(s)gG^{(s)} (for g∈Gg \in G and s∈Ss \in S), and C\mathscr{C} the set of subsets of II of the form Cg={gG(s)∣s∈S}C_g = \{ gG^{(s)} \mid s \in S \} for g∈Gg \in G. The CgC_g are called the chambers of II (§ 1, Exerc. 15). Let GG act on II by left translations.

a) Let F\mathfrak{F} be the set of facets of II (that is, the subsets of the chambers, cf. § 1, Exerc. 15). Let F∈FF \in \mathfrak{F}. Show that there exist a unique subset XX of SS and an element g∈Gg \in G such that gGX=⋂a∈FagG_X = \bigcap_{a \in F} a; FF is said to be of type XX. Show that FF is then the set of gG(s)gG^{(s)} for s∈S−Xs \in S - X and is of codimension Card(X)\mathrm{Card}(X) in any chamber containing it. Show that the map j:F↦⋂a∈Faj : F \mapsto \bigcap_{a \in F} a is a strictly decreasing bijection, compatible with left translations, from F\mathfrak{F} to the set of subsets of GG of the form gGXgG_X for g∈Gg \in G and X⊂SX \subset S. Show that, if X⊂Y⊂SX \subset Y \subset S, every facet of type XX contains a unique facet of type YY.

b) Show that GG acts transitively on the set C\mathscr{C} of chambers and that the stabilizer of the chamber CgC_g (g∈Gg \in G) is equal to gBg−1gB g^{-1}; the map g↦Cgg \mapsto C_g thus defines a bijection from G/BG/B to C\mathscr{C}.

c) Show that two chambers CgC_g and Cg′C_{g'} (g,g′∈Gg, g' \in G) are neighbouring (§ 1, Exerc. 15) if and only if there exists s∈Ss \in S such that g′∈g(B∪BsB)g' \in g(B \cup BsB).

d) Let C1,…,CnC_1, \ldots, C_n be chambers of II and put C0=CeC_0 = C_e. Show that the following conditions are equivalent: (i) the sequence Γ=(C0,C1,…,Cn)\Gamma = (C_0, C_1, \ldots, C_n) is an injective gallery; (ii) there exist a sequence s=(s1,…,sn)s = (s_1, \ldots, s_n) of elements of SS and a sequence (b1,…,bn)(b_1, \ldots, b_n) of elements of BB such that Cj=b1sˉ1b2sˉ2…bjsˉj(C0)C_j = b_1 \bar{s}_1 b_2 \bar{s}_2 \ldots b_j \bar{s}_j (C_0) (where sˉj\bar{s}_j denotes a given element of the double coset BsjBBs_j B) for 1≤j≤n1 \leq j \leq n.

Show that, if these conditions are satisfied, the sequence s is unique: it is then called the type of Γ\Gamma and denoted by s(Γ′)s(\Gamma'). Show that an injective gallery is minimal if and only if its type is a reduced decomposition. Show that the following conditions are satisfied:

(WI 1) For any two chambers C and C' of I, there exists a unique element t(C, C') of W such that the set of types of minimal galleries with extremities C and C' is the set of reduced decompositions of t(C, C').

(WI 2) For any chamber C, the map C' ↦t(C,C′)\mapsto t(C, C') from the set of chambers of I to W is surjective.

e) Show that two minimal galleries of the same type and with the same extremities are identical. (Reduce to proving that, if (s1,…,sn)(s_1, \ldots, s_n) is a reduced decomposition and if b1,…,bn,b1′,…,bn′b_1, \ldots, b_n, b'_1, \ldots, b'_n are elements of B such that b1sˉ1…bnsˉn∈b1′sˉ1…bn′sˉnBb_1 \bar{s}_1 \ldots b_n \bar{s}_n \in b'_1 \bar{s}_1 \ldots b'_n \bar{s}_n B, then b1sˉ1∈b1′sˉ1Bb_1 \bar{s}_1 \in b'_1 \bar{s}_1 B. For this, remark that if sˉ1−1b1−1b1′sˉ1∉B\bar{s}_1^{-1} b_1^{-1} b'_1 \bar{s}_1 \notin B, then this element would belong to Bs_1B and we would have b2sˉ2…bnsˉn∈bsˉ1b′b2′sˉ2…bn′sˉnBb_2 \bar{s}_2 \ldots b_n \bar{s}_n \in b \bar{s}_1 b' b'_2 \bar{s}_2 \ldots b'_n \bar{s}_n B with b,b′∈Bb, b' \in B, contradicting Cor. 1 of Th. 2 of no. 4.)

f) Show that I equipped with C\mathscr{C} is a building, said to be associated to the pair (G, B). Show that there exists a unique numbering (§1§ 1, Exerc. 20) of I for which the type of a facet is that defined in a).

g) Show that I is spacious, namely that every panel of I is contained in at least three chambers (cf. §1§ 1, Exerc. 24). Show that the following condition is satisfied:

(G) Given a panel F, a chamber C, a gallery Γ=(C0,…,Cn)\Gamma = (C_0, \ldots, C_n) such that F⊂CnF \subset C_n and of smallest possible length, and chambers C′C' and C′′C'' containing F and distinct from CnC_n, there exists an element g∈Gg \in G such that g(Ci)=Cig(C_i) = C_i for 0≤i≤n0 \leq i \leq n and g(C′)=C′′g(C') = C''.

(Reduce to the case C0=CC_0 = C; let u∈Su \in S be such that F is of type S−{u}S - \{u\} and let s be the type of Γ\Gamma. Show that (s,u)(s, u) is a reduced decomposition. Take h∈Gh \in G such that Cn=h(C)C_n = h(C); there exist b′b' and b′′∈Bb'' \in B such that C′=hb′u(C)C' = hb'u(C) and C′′=hb′′u(C)C'' = hb''u(C). Then use Cor. 1 of Th. 2 of no. 4 generalized to the case of a Tits subgroup (cf. Exerc. 3 f)) to show that there exists b∈Bb \in B such that bb′b′uB=hb′′uBbb'b'uB = hb''uB; then b∈hBuBu−1Bh−1⊂(hBh−1)∪(hBuBh−1)b \in hBuBu^{-1}Bh^{-1} \subset (hBh^{-1}) \cup (hBuBh^{-1}). If b∈hBuBh−1b \in hBuBh^{-1}, we would have BhB⊂BhBuB=BhuBBhB \subset BhBuB = BhuB (loc. cit.), which is impossible. Hence b(Cn′)=Cnb(C_{n'}) = C_n and e) implies that b(Ci)=Cib(C_i) = C_i for all ii.)

Solution

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