Bourbaki

Exercise 12, § 11

General Topology, I, 156

Let X be a topological space. Show that the following three conditions are equivalent: α\alpha the components of X are open sets; β\beta every x∈Xx \in X has a neighbourhood contained in every set which is both open and closed and contains x; γ\gamma for every x∈Xx \in X, the intersection of the sets which are both open and closed and contain x is an open set.

Solution

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Transcribed from the printed volume. Not translated.