Exercise 6, § 2
General Topology, I, 120
Bourbaki marks this one as harder than the rest.
A topology on a set is said to be quasi-maximal if it is maximal in the set of topologies in which has no isolated points.
a) Show that the following properties of a topology on are equivalent: is quasi-maximal; if carries the topology , then has no isolated point and every subset of which has no isolated points is open.
b) Let be a Kolmogoroff space (, Exercise 2) in which every non-empty open set is infinite. Show that there exists a quasi-maximal topology on which is finer than the given topology (show that the set of topologies on in which all the non-empty open sets are infinite is inductive, and use Exercise 2 d) of ).
Solution
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