Exercise 28, § 8
General Topology, I, 141
Let be a Hausdorff space which is not regular, let be a closed subset of and let be a point of such that every neighbourhood of meets every neighbourhood of . Let be the equivalence relation on obtained by identifying all the points of . Show that is closed and that the graph of is closed in , but that is not Hausdorff.
Solution
No solution has been written yet.