Bourbaki

Exercise 3, § 8

General Topology, I, 134

a) Let XX be an accessible space, AA a subset of XX, and xx a point of A‾\overline{A} which does not belong to AA. Show that every neighbourhood of xx contains an infinite number of points of AA.

b) Let XX be an accessible space and let AA be a subset of XX. Show that the set of points x∈A‾x \in \overline{A} such that every neighbourhood of xx contains a point of AA other than xx is closed in XX.

c) Let XX be an accessible space. Show that the intersection of all neighbourhoods of any subset AA of XX is equal to AA.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.