Bourbaki

Exercise 4, § 8

General Topology, I, 134

Show that every subspace of a Kolmogoroff space (resp. accessible space) is a Kolmogoroff space (resp. accessible space); and that a topology which is finer than a topology of a Kolmogoroff space (resp. accessible space) is the topology of a Kolmogoroff space (resp. accessible space).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.