Bourbaki

Exercise 23, § 4

General Topology, II, 215

Bourbaki marks this one as harder than the rest.

Let f : X → Y be a continuous open mapping, X locally compact and Y Hausdorff.

a) If K is any compact connected subset of Y and C is any compact component of f‾(K)\overline{f}(K), show that f(C)=Kf(C) = K (reduce to the case K = Y and use the Corollary to Proposition 6 of no. 4). Give an example of a non-compact component C' of f‾(K)\overline{f}(K) such that f(C′)≠Kf(C') \neq K.

b) Suppose in addition that Y is locally compact and locally connected. Show that if U is any connected open subset of Y and R is any relatively compact component of f‾(U)\overline{f}(U) in X, then f(R)=Uf(R) = U. [Observe that in a locally compact locally connected space, a connected open set U is the union of the compact connected sets contained in U and containing a given point y0∈Uy_0 \in U; then apply a).]

c) Suppose in addition that X is locally connected. Show that if K is any connected subset of Y which is either open or compact with a non-empty interior, and if H is any compact subset of X, then there is only a finite number of components of f‾(K)\overline{f}(K) contained in H. [Use a) and b)].

Solution

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