Bourbaki

Exercise 2, § 1

General Topology, III, 296

A semi-topological group is a group GG endowed with a topology such that, for each a∈Ga \in G, the translations x→axx \to ax and x→xax \to xa are continuous on GG, and such that the symmetry x→x−1x \to x^{-1} is continuous on GG (*).

a) A filter B\mathfrak{B} on a group GG is the neighbourhood filter of ee in a topology which makes GG a semi-topological group if and only if B\mathfrak{B} satisfies axioms (GVII)(\mathrm{GV}_{\mathrm{II}}) and (GVIII)(\mathrm{GV}_{\mathrm{III}}) and the family of filters

B(x)=x.B=B.x(x∈G) \mathfrak{B}(x) = x.\mathfrak{B} = \mathfrak{B}.x \quad (x \in G)
satisfies axiom (VIV)(\mathrm{V}_{\mathrm{IV}}) of Chapter I, § 1, no. 2.

b) If GG is an infinite group, show that the topology in which the open sets are ∅\varnothing and the complements of finite subsets of GG makes GG a non-Hausdorff semi-topological group in which {e}\{e\} is closed, but is not compatible with the group structure of GG.

c) Define a topology on R\mathbf{R}, finer than the usual topology, for which R\mathbf{R} is a semi-topological but not topological group [consider a decreasing sequence (rn)(r_n) of numbers >0> 0, tending to 00, and take the intersections of symmetric intervals ]—a,a[a, a[ and of the complement of the set of points ±rn\pm r_n. \

(*) If GG is locally compact these conditions imply that the topology of GG is compatible with its group structure (Chapter X, § 3, Exercise 25).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.