Bourbaki

Exercise 19, § 4

General Topology, III, 312

Bourbaki marks this one as harder than the rest.

Let GG be a locally compact group, let G0G_0 be the identity component of GG, and let HH be a closed subgroup of GG. Show that if the homogeneous space G/HG/H is locally connected, then G0HG_0H is open in GG. Let H0H_0 be the identity component of HH; then there is an open subgroup LL of HH such that L/H0L/H_0 is compact (no. 6, Corollary 1 to Proposition 14); show that on the one hand LG0LG_0 is closed in GG, by using Corollary 1 of Proposition 1, and on the other hand that LG0LG_0 is open in G, by considering the canonical image of G0G_0 in G/LG/L and using Corollary 3 of Proposition 14 and the fact that a quotient space of a locally connected space is locally connected [Chapter I, § 11, no. 6, Proposition 12)].

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.