Bourbaki

Exercise 1, § 7

General Topology, III

a) Show that the ring Zp\mathbf{Z}_p of pp-adic integers [§ 6, Exercise 23 a)] is isomorphic to the inverse limit of the sequence of discrete rings Z/(pn)\mathbf{Z}/(p^n), fnm:Z/(pm)→Z/(pn)f_{nm}: \mathbf{Z}/(p^m) \to \mathbf{Z}/(p^n) for n≤mn \leq m being the canonical homomorphism when Z/(pn)\mathbf{Z}/(p^n) is considered as a quotient ring of Z/(pm)\mathbf{Z}/(p^m).

b) For each integer n>0n > 0, let GnG_n be the group Z\mathbf{Z} of rational integers, and let XnX_n be its quotient group Z/(pn)\mathbf{Z}/(p^n) (pp prime), GnG_n and XnX_n carrying the discrete topology; consider (Gn)(G_n) as an inverse system, Gm→GnG_m \to G_n being the identity mapping; and consider (Xn)(X_n) as an inverse system, fnm:Xm→Xnf_{nm}: X_m \to X_n being the canonical homomorphism (see a) for n≤mn \leq m. Then the orbit of each point of XnX_n with respect to GnG_n is compact, but the orbit of a point x=(xn)x = (x_n) of X=lim←⁡XnX = \varprojlim X_n with respect to G=lim←⁡GnG = \varprojlim G_n is not compact, and is not isomorphic to the inverse limit of the orbits of the xnx_n; also the canonical mapping X/G→lim←⁡Xn/GnX/G \to \varprojlim X_n/G_n is not injective.

c) For each n>0n > 0, let GnG_n be the subgroup pnZp^n\mathbf{Z} of Z\mathbf{Z} (pp prime), and let XnX_n be the group Z\mathbf{Z}, where GnG_n and XnX_n carry the discrete topology and GnG_n operates by translations on XnX_n. Consider (Gn)(G_n) and (Xn)(X_n) as inverse systems, Xm→XnX_m \to X_n being the identity mapping and Gm→GnG_m \to G_n the canonical injection (n≤m)(n \leq m). Then the stabilizer of each point of XnX_n (with respect to GnG_n) is compact, the orbit of each point of X=lim←⁡XnX = \varprojlim X_n with respect to G=lim←⁡GnG = \varprojlim G_n is compact, but the canonical mapping X/G=lim←⁡Xn/GnX/G = \varprojlim X_n/G_n is not surjective.

d) Construct, using b) and c), an example of an inverse system of spaces with operators (Xα)(X_\alpha) with respect to an inverse system of groups (Gα)(G_\alpha), such that, if X=lim←⁡XαX = \varprojlim X_\alpha and G=lim←⁡GαG = \varprojlim G_\alpha, the canonical mapping X/G→lim←⁡Xα/GαX/G \to \varprojlim X_\alpha / G_\alpha is neither injective nor surjective.

Solution

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Transcribed from the printed volume. Not translated.