Exercise 4, § 1
General Topology, IV, 380
Bourbaki marks this one as harder than the rest.
a) Let be a linearly ordered set. Let be the -module of formal finite linear combinations of elements of with coefficients in , and define a linearly ordered group structure on by taking the set of elements to be the set consisting of and all linear combinations such that for the largest element such that . Show that can be identified with a cofinal subset of .
b) Suppose that is well-ordered, and consider the group of bounded mappings of into . Define a linearly ordered group structure on by taking the set of elements to be the set consisting of and all bounded mappings of into such that for the smallest such that (lexicographic ordering). Show that is complete with respect to the topology ; if moreover is uncountable and is such that every segment is countable, then every countable intersection of open sets in is open, and every compact subset of is finite (cf. Chapter I, § 9, Exercise 4).
c) Suppose henceforth that E is well-ordered and uncountable but that every segment ]←, ξ] is countable. For each ξ ∈ E, let c_ξ be the constant mapping of E into E whose value at every point is ξ. The c_ξ form a cofinal subset in G_+. Let E_0 be a set obtained by adjoining an element ω to E, and consider the topology , on the set X = G × E_0, generated by the following sets: (i) V_{a, b, ξ} = ]a, b[ × {ξ} for a < b in G and ξ ∈ E; (ii) W_{a, b, ξ} — for a < b in G and ξ ∈ E such that c_ξ > sup (|a|, |b|) — consisting of the pairs (x, ω) such that a < x < b, and the pairs (x, ζ) such that ζ ∈ E, ζ ≥ ξ and either a < x < b or 4c_ζ + a < x < 4c_ζ + b. Show that is Hausdorff and that every compact subset of X (with respect to ) is finite. Moreover G operates continuously on X according to the law (x, (y, ζ)) → (x + y, ζ); but G does not operate properly on X, although conditions a), b), c) and d) of Chapter III, § 4, no. 2, Proposition 4 are satisfied and although, for each pair of compact subsets K, L of X, the set P(K, L) (Chapter III, § 4, no. 5, Theorem 1) is compact.
Solution
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