Bourbaki

Exercise 14, § 2

General Topology, IV

Bourbaki marks this one as harder than the rest.

Let XX be a connected Hausdorff topological space not consisting of a single point, and let Δ\Delta denote the diagonal of X×XX \times X.

a) Show that there is no partition of CΔC\Delta into two open sets D1,D2D_1, D_2 such that D1−1=D1D_1^{-1} = D_1 and D2−1=D2D_2^{-1} = D_2. [Begin by remarking that D1(x)D_1(x) and D2(x)D_2(x) are connected for each x∈Xx \in X (use Exercise 4 a) of Chapter I, § 11); deduce that, if y∈D1(x)y \in D_1(x), we have D2(x)×{y}⊂D1D_2(x) \times \{y\} \subset D_1, and show that this implies that, for each x∈Xx \in X, one or the other of the sets D1(x)D_1(x), D2(x)D_2(x) is empty; hence show that one or the other of the sets D1,D2D_1, D_2 is empty, which is contrary to hypothesis.] Deduce that either CΔC\Delta is connected or else CΔC\Delta has exactly two components A,BA, B such that B=A−1B = A^{-1}.

b) A linear ordering on XX is said to be compatible with the topology T\mathfrak{T} of XX if T0(X)\mathfrak{T}_0(X) is coarser than T\mathfrak{T}. Deduce from a) that there exists such a linear ordering on XX if and only if CΔC\Delta is not connected, and that there are then exactly two such linear orderings. [With the notation of a), show that the order relation must be either (x,y)∈A(x, y) \in A or (x,y)∈B=A−1(x, y) \in B = A^{-1}.] Show that the intervals, for these orderings, are connected in the topology T\mathfrak{T}, and that they are the only connected subsets of XX with respect to T\mathfrak{T}.

c) Show that if XX is either locally connected or locally compact in the topology T\mathfrak{T}, and if there exists a linear ordering on XX compatible with T\mathfrak{T}, then we must have T=T0(X)\mathfrak{T} = \mathfrak{T}_0(X). [If XX is locally connected, use b). If XX is locally compact, show that every compact neighbourhood of a point x∈Xx \in X is also a neighbourhood of xx with respect to T0(X)\mathfrak{T}_0(X), by considering the frontier of the neighbourhood].

d) Let XX be the subspace of R2\mathbf{R}^2 consisting of (0,0)(0, 0) and all pairs (x,y)(x, y) such that x>0x > 0 and y=sin⁡(1/x)y = \sin(1/x). Show that there exists a linear ordering on XX which is compatible with the topology induced on XX by the topology of R2\mathbf{R}^2, but that this topology is strictly finer than T0(X)\mathfrak{T}_0(X). \ Give an example of a connected Hausdorff space XX, no point of which has a fundamental system of connected neighbourhoods, and on which there is a linear ordering compatible with the topology of XX [cf. Chapter I, § 11, Exercise 2 b)].

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.