Bourbaki

Exercise 19, § 2

General Topology, IV

Bourbaki marks this one as harder than the rest.

a) Let XX be a connected Hausdorff space and let a,ba, b be two distinct points of XX such that there is no connected \emph{closed} subset of XX, other than XX itself, which contains both aa and bb. If xx is a point of XX other than aa or bb, then C{x}C\{x\} is not connected if and only if, for each y∈C{x}y \in C\{x\}, there is in C{y}C\{y\} a connected subset which is closed in XX and contains xx and one of the points a,ba, b. [To show that the condition is necessary, use Exercise 4 a) of Chapter I, § 11; to show that it is sufficient, let AA (resp. BB) be the set of all y∈Xy \in X such that there is a connected subset of C{y}C\{y\} which is closed in XX and contains aa and xx (resp. bb and xx); show that AA and BB are non-empty and open and disjoint from each other, and that C{x}=A∪BC\{x\} = A \cup B.

b) Let XX be a compact connected space which is irreducible between two of its points a,ba, b (Chapter II, § 4, Exercise 19). Show that if for each pair of distinct points x,yx, y of XX there is a compact connected set in XX which contains yy and one of a,ba, b but does not contain xx, then there is a linear ordering on XX such that T0(X)\mathfrak{T}_0(X) is the given topology on XX (Exercises 15 and 16).

Solution

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Transcribed from the printed volume. Not translated.