Bourbaki

Exercise 13, § 4

General Topology, IX

Bourbaki marks this one as harder than the rest.

Let (Xi)i∈I(X_i)_{i \in I} be an uncountable family of Hausdorff topological spaces, each containing more than one point. For each i∈Ii \in I, let aia_i and bib_i be two distinct points of XiX_i. Let XX be the product space ∏i∈IXi\prod_{i \in I} X_i, and let YY be the subspace of XX consisting of these points (xi)i∈I(x_i)_{i \in I} such that xi=aix_i = a_i for all but a countable set of indices ii; and let bb be the point bib_i of XX.

In the product space X×YX \times Y, let AA be the diagonal of Y×YY \times Y and let BB be the set {b}×Y\{b\} \times Y. Show that AA and BB are closed sets and that there is no pair of open sets U,VU, V in X×YX \times Y such that A⊂U,B⊂VA \subset U, B \subset V, and U∩V=∅U \cap V = \emptyset. [Let U,VU, V be two open sets such that A⊂UA \subset U and B⊂VB \subset V; show that there is an increasing sequence (Hn)(H_n) of countable subsets of II, such that if xnx_n denotes the point of YY for which each coordinate with index i∈Hni \in H_n is equal to bib_i, and each coordinate with index i∉Hni \notin H_n is equal to aia_i, then the point (xn+1,xn)(x_{n+1}, x_n) belongs to VV for each integer nn; prove that the sequence (xn+1,xn)(x_{n+1}, x_n) tends to a point of AA, and deduce that U∩V≠∅U \cap V \neq \emptyset.]

Hence construct an example of a connected topological ring which is not normal.

Deduce also that the product of an uncountable family of Hausdorff topological spaces, each of which has at least two distinct points, cannot be completely normal (use the result above when each XiX_i is a discrete space of two points).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.