Bourbaki

Exercise 1, § 2

General Topology, VI

It is set in small type as supplementary.

Let II be the closed cube of Rn\mathbf{R}^n which is the product of nn intervals identical with [−12π,12π][-\frac{1}{2}\pi, \frac{1}{2}\pi]. To each point x=(xi)x = (x_i) of II we make correspond the point y=(yj)y = (y_j) of Rn+1\mathbf{R}^{n+1} such that

y1=sin⁡x1y2=cos⁡x1sin⁡x2⋯yp=cos⁡x1cos⁡x2…cos⁡xp−1sin⁡xp(2≤p≤n−1)⋯yn=cos⁡x1cos⁡x2…cos⁡xn−1sin⁡2xnyn+1=cos⁡x1cos⁡x2…cos⁡xn−1cos⁡2xn. \begin{align*} y_1 &= \sin x_1 \\ y_2 &= \cos x_1 \sin x_2 \\ &\cdots \\ y_p &= \cos x_1 \cos x_2 \ldots \cos x_{p-1} \sin x_p \quad (2 \leq p \leq n-1) \\ &\cdots \\ y_n &= \cos x_1 \cos x_2 \ldots \cos x_{n-1} \sin 2x_n \\ y_{n+1} &= \cos x_1 \cos x_2 \ldots \cos x_{n-1} \cos 2x_n. \end{align*}

Show that the image of I under this mapping is the sphere SnS_n, and that the restriction of this mapping to the interior of I is a homeomorphism onto a dense open set in SnS_n. \*

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.