Exercise 1, § 1
General Topology, VII
Let G be a discrete subgroup of rank in and let be a free system of points of G. The proof of Theorem 1 of no. 1 shows that G is a subgroup of the group generated by the points , where is some integer. Show, without using Theorem 1, that there exists a free system of points of G such that, if is any free system of points of G, we have . Hence give a proof of Theorem 1 which does not rest on the theory of invariant factors, by showing that the generate G. (Argue by contradiction: if and one of the is not an integer, there exists a point of the group generated by and the such that for some index , and hence obtain a contradiction.)
Solution
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