Bourbaki

Exercise 11, § 1

General Topology, VII

Let ai=(aij)a_i = (a_{ij}) (1≤i≤m, 1≤j≤n1 \leq i \leq m,\ 1 \leq j \leq n) be mm points of Rn\mathbf{R}^n and let qq be an integer > o. For each point k=(ki)k = (k_i) (1≤i≤m1 \leq i \leq m) of Rm\mathbf{R}^m with integer coordinates, not all zero, satisfying the inequalities 0≤ki≤q0 \leq k_i \leq q, consider the point xk=(xj,k)x_k = (x_{j,k}) (1≤j≤n1 \leq j \leq n) of Rn\mathbf{R}^n, all of whose coordinates belong to [0,1[[0, 1[ and which is congruent mod Zn\mathbf{Z}^n to ∑i=1mkiai\sum_{i=1}^m k_i a_i, i.e., the point with coordinates

xj,k=∑i=1mkiaij−[∑i=1mkiaij]. x_{j,k} = \sum_{i=1}^m k_i a_{ij} - \left[ \sum_{i=1}^m k_i a_{ij} \right].

If pp is the smallest integer such that q+1≥pn/mq + 1 \geq p^{n/m}, show that there are two distinct points k,k′k, k' such that xkx_k and xk′x_{k'} both belong to the same cube of side 1/p1/p (same method as Exercise 10). Deduce that there exist mm integers pip_i, not all zero, and nn integers rjr_j (1≤j≤n1 \leq j \leq n) such that 0≤pi≤q0 \leq p_i \leq q for 1≤i≤m1 \leq i \leq m, and

∣∑i=1mpiaij−rj∣≤1p(1≤j≤n). \left| \sum_{i=1}^m p_i a_{ij} - r_j \right| \leq \frac{1}{p} \quad (1 \leq j \leq n).

Use this result to give another proof of Proposition 2 of no. 1 (the "pigeon-hole principle").

Solution

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Transcribed from the printed volume. Not translated.