Bourbaki

Exercise 22, § 3

General Topology, X

Bourbaki marks this one as harder than the rest.

Let XX be a compact space, and let TT be a subgroup of the group of all homeomorphisms of XX, endowed with a locally compact topology T\mathscr{T} for which condition (A) of Exercise 21 is satisfied. Let GG be a countable subgroup of TT, and let ff be a continuous real-valued function on XX. Consider the continuous mapping x→φ(x)x \to \varphi(x) of XX into IGI^G, where I=f(X)⊂RI = f(X) \subset \mathbf{R} and φ(x)=(f(u(x)))u∈G\varphi(x) = (f(u(x)))_{u \in G}. Let YY be the image of XX under φ\varphi; YY is a compact metrizable subspace of IGI^G.

a) Show that the set of all v∈Tv \in T such that φ∘v=φ\varphi \circ v = \varphi is a subgroup KK of TT whose normalizer in TT contains GG. Let RR be the equivalence relation u∘v−1∈Ku \circ v^{-1} \in K on TT, and let T′T' be the quotient space T/RT/R and p:T→T/Rp : T \to T/R the canonical mapping. Show that T′T' is locally compact, and that if we set p(u)v=p(u∘v)p(u)v = p(u \circ v), then TT operates on the right on T′T' in such a way that t′→t′vt' \to t'v is continuous on T′T' for all v∈Tv \in T.

b) Let G′=p(G)G' = p(G), let H′H' be the closure of G′G' in T′T', and let H=p−1(H′)H = p^{-1}(H'). Show that, if u∈Hu \in H, the relation p(v)=p(v′)p(v) = p(v') implies p(u∘v)=p(u∘v′)p(u \circ v) = p(u \circ v') so that HH operates on the left on T′T'; moreover, if we set up(v)=p(u∘v)up(v) = p(u \circ v) for u∈H,v∈Tu \in H, v \in T, then the mapping t′→ut′t' \to ut' is continuous on T′T'. Finally, if u1,u2u_1, u_2 are elements of HH such that p(u1)=p(u2)p(u_1) = p(u_2), we have u1t′=u2t′u_1t' = u_2t'; hence, by passing to the quotient, we define a mapping (u′,t′)→u′t′(u', t') \to u't' of H′×T′H' \times T' into T′T', such that t′→u′t′t' \to u't' is continuous on T′T' for all u′∈H′u' \in H'. Show that if u′∈H′u' \in H' and v′∈H′v' \in H', then u′v′∈H′u'v' \in H' and that the law of composition so defined on H′H' induces a group structure on G′G' (with respect to which G′G' is isomorphic to GK/KGK/K).

c) If u∈Hu \in H, the relation φ(x)=φ(y)\varphi(x) = \varphi(y) implies φ(u(x))=φ(u(y))\varphi(u(x)) = \varphi(u(y)) and consequently there is a unique mapping u~:Y→Y\tilde{u} : Y \to Y such that φ∘u=u~∘φ\varphi \circ u = \tilde{u} \circ \varphi. Show that u~\tilde{u} is continuous and surjective and that u~1=u~2\tilde{u}_1 = \tilde{u}_2 if and only if p(u1)=p(u2)p(u_1) = p(u_2); this allows us to write u~=u~′\tilde{u} = \tilde{u}', where u′=p(u)u' = p(u), and defines an injective mapping ψ:u′→u~′\psi : u' \to \tilde{u}' of H′H' into Cs(Y;Y)C_s(Y; Y). Show that ψ\psi is continuous and that ψ(u′v′)=ψ(u′)∘ψ(v′)\psi(u'v') = \psi(u') \circ \psi(v'); using ψ\psi to identify H′H' with a subset of Cs(Y;Y)C_s(Y; Y) and denoting by T′\mathscr{T}' the topology on H′H' induced by that of T′T', show that (H′,T′)(H', \mathscr{T}') satisfies property (A) of Exercise 21.

d) Show that, if GG is endowed with the topology induced by T\mathscr{T}, the mapping (u,x)→u(x)(u, x) \to u(x) of G×XG \times X into XX is continuous. [Show that, for every continuous real-valued function ff on XX, the mapping (u,x)→f(u(x))(u, x) \to f(u(x)) is continuous on G×XG \times X, by using c) and Exercise 21; then apply Chapter IX, § 1, no. 5, Proposition 4.]

Solution

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