Bourbaki

Proposition 2

Tag 0007, permanent. Cite it as [Bourbaki, Tag 0007].

Algebra, VIII, p. 3, § 1. Artinian Modules and Noetherian Modules

An A-module M is Noetherian if and only if every submodule of M is finitely generated.

Begin by assuming that every submodule of M is finitely generated. Let (Pn)n∈N(P_n)_{n\in\mathbf{N}} be an increasing sequence of submodules of M, and let P be its union. This is a submodule of M. By assumption, there exists a finite subset F of M generating the module P; let n∈Nn\in \mathbf{N} be an integer such that F⊂PnF\subset P_n. We then have Pn=PP_n= P, and the sequence (Pn)n∈N(P_n)_{n\in\mathbf{N}} is stationary. This proves that the module M is Noetherian.

The converse is a consequence of the following more precise statement.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.