Bourbaki

Proposition 4

Tag 000L, permanent. Cite it as [Bourbaki, Tag 000L].

Algebra, VIII, p. 7, § 1. Artinian Modules and Noetherian Modules

a) Let A be a left Noetherian ring and M a finitely generated left A-module. The module M is Noetherian, and every submodule of M is finitely generated.

b) Let A be a left Artinian ring and M a left A-module. The following properties are equivalent: the module M is finitely generated; the module M is Artinian; the module M has finite length; the module M is Noetherian.

Let us prove a). Every monogenous submodule of M is isomorphic to a quotient of AsA_s, hence is Noetherian by Proposition 3 of VIII, p. 3. The module M is a finite sum of such submodules; it is therefore Noetherian by the corollary (VIII, p. 4) of Proposition 3. Every submodule of M is then finitely generated (VIII, p. 3, Proposition 2)

Now, suppose that the ring A is left Artinian. We see, as in the previous section, that if the A-module M is finitely generated, then it is Artinian. If it is Artinian, then it has finite length: indeed, its monogenous submodules are isomorphic to quotients of AsA_s and are therefore of finite length less than that of AsA_s, and the assertion follows from Lemma 3. Every module of finite length is Noetherian, and every Noetherian module is finitely generated. This proves b).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.