Bourbaki

Lemma 2

Tag 005O, permanent. Cite it as [Bourbaki, Tag 005O].

Algebra, VIII, p. 82, § 5. Commutation

Let A be a ring and M a projective A-module. The AMA_M-module M is projective.

Let (xi)i∈I(x_i)_{i\in I} be a generating family of the A-module M. There exists a family (xi∗)i∈I(x^*_i)_{i\in I} of linear forms on the A-module M such that for every x∈Mx\in M, the family (⟨x,xi∗⟩)i∈I(\langle x, x^*_i\rangle )_{i\in I} has finite support and x=∑i∈I⟨x,xi∗⟩xix=\sum_{i\in I}\langle x, x^*_i\rangle x_i (II, §2, No. 6, p. 238, Proposition 12). For every i∈Ii\in I, the mapping x↦⟨x,xi∗⟩Mx\mapsto \langle x, x^*_i\rangle_M is a linear form on the AMA_M-module M, and we have x=∑i∈I⟨x,xi∗⟩Mxix=\sum_{i\in I}\langle x, x^*_i\rangle_Mx_i for every x∈Mx\in M. By loc. cit., M is a projective AMA_M-module.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Cites

  • II, §2, No. 6, p. 238, Proposition 12 not in this corpus
Transcribed from the printed edition, 2023, Springer Nature. Not translated.