Bourbaki

Exercise 19, § 5

Tag 006Q, permanent. Cite it as [Bourbaki, Tag 006Q].

Algebra, VIII, p. 94

Bourbaki marks this one as harder than the rest.

Let A be a ring such that the A-module AsA_s is the direct sum of a finite family of left ideals (Ii)1⩽i⩽n(\mathfrak{I}_i)_{1\leqslant i\leqslant n} that are isomorphic as A-modules.

a) Prove that in A, there exists a family of elements ei,j(1⩽i⩽n,1⩽j⩽n)e_{i,j}(1\leqslant i\leqslant n, 1\leqslant j\leqslant n) such that ei,jeh,k=δj,hei,ke_{i,j}e_{h,k}=\delta_{j,h}e_{i,k}, where δj,h\delta_{j,h} denotes the Kronecker delta function, and Ii=Aei,i\mathfrak{I}_i= Ae_{i,i} (cf. VIII, p. 39, Exercise 5 and I, §8, p. 173, Exercise 12). Conversely, if in A, there exists a family of n2n^2 elements ei,je_{i,j} such that ei,jeh,k=δj,hei,ke_{i,j}e_{h,k}=\delta_{j,h}e_{i,k} and 1=∑i=1nei,i1 =\sum^n_{i=1}e_{i,i}, then the left ideals Aei,iAe_{i,i} are isomorphic as A-modules (cf. VIII, p. 39, Exercise 5). Moreover, if B is the subring of A consisting of the elements that commute with all the ei,je_{i,j}, then A is isomorphic to the matrix ring Mn(B)\mathbf{M}_n(B) and B is isomorphic to the opposite ring of the commutant of each of the A-modules Aei,iAe_{i,i} (use VIII, p. 78 and VIII, p. 65, Corollary).

b) Let M be an A-module. Prove that the Ni=ei,iMN_i=e_{i,i}M are B-modules and that M, viewed as a B-module, is the direct sum of the NiN_i; moreover, the B-modules NiN_i are pairwise isomorphic (consider the mappings x↦ei,1xx\mapsto e_{i,1}x and y↦e1,iyy\mapsto e_{1,i}y), and the annihilator of the NiN_i is the intersection of B and the annihilator of M in A. Conversely, for every B-module N, define an A-module structure on the direct sum M of nn B-modules isomorphic to N, so that e1,1Me_{1,1}M is isomorphic to N.

c) To each B-submodule P of N1N_1, assign the A-submodule ∑i=1nei,1P\sum^n_{i=1}e_{i,1}P of M. Prove that this defines a bijective mapping from the set of B-submodules of N1N_1 to the set of A-submodules of M that is strictly increasing for the inclusion relation.

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