Bourbaki

Exercise 7, § 6

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Algebra, VIII, p. 116

Keep the previous assumptions. Suppose, moreover, given

– an A-module G(N) for every B-module N,

– an A-linear homomorphism G(v):G(N)→G(N′)G(v) : G(N)\rightarrow G(N') for every homomorphism of B-modules v:N→N′v: N\rightarrow N',

– an isomorphism αM:M→G(F(M))\alpha_M: M\rightarrow G(F(M)) for every A-module M, and

– an isomorphism βN:N→F(G(N))\beta_N: N\rightarrow F(G(N)) for every B-module N.

Suppose that the construction G has the properties analogous to (i) through (iii) above, that for every A-module homomorphism u:M→M′u: M\rightarrow M', we have G(F(u))∘αM=G(F(u))\circ \alpha_M= αM′∘u\alpha_{M'}\circ u, and that for every B-module homomorphism v:N→N′v: N\rightarrow N', we have F(G(v))∘βN=βN′∘vF(G(v))\circ \beta_N=\beta_{N'}\circ v.

a) Let M and M′M' be A-modules; prove that the homomorphism u↦F(u)u\mapsto F(u) is an isomorphism from HomA(M,M′)_A(M,M') to HomB(F(M),F(M′))_B(F(M),F(M')).

b) Let f∈f\in HomA(M,M′)_A(M,M'); then F(f)F(f) is injective (resp. surjective) if and only if ff is (observe that ff is injective if and only if for every A-module E and every nonzero homomorphism g:E→Mg: E\rightarrow M, we have f∘g≠0f\circ g\not= 0).

c) Let 0→M′→iM→pM′′→00\rightarrow M'\rightarrow^iM\rightarrow^pM''\rightarrow 0 be an exact sequence of A-modules; prove that the sequence 0→F(M′)→F(i)F(M)→F(p)F(M′′)→00\rightarrow F(M')\overset{F(i)}{\rightarrow}F(M)\overset{F(p)}{\rightarrow}F(M'')\rightarrow 0 is exact.

d) Let (Mα)α∈I(M_{\alpha})_{\alpha\in I} be a family of A-modules, and let M be its direct sum. Construct a canonical isomorphism from ⊕F(Mα)\oplus F(M_{\alpha}) to F(M).

e) Let M be an A-module. Show that F(M) is projective (resp. generating, resp. finitely generated) if and only if M is (use Exercise 9 of VIII, p. 92).

f ) Prove that the (B(B, A)-bimodule F(As)F(A_s) is invertible and that the (A(A, B)-bimodule G(Bs)G(B_s) is an inverse.

g) Prove that for every A-module M, the homomorphism θM:F(As)⊗AM→F(M)\theta_M: F(A_s)\otimes_AM\rightarrow F(M) defined in Exercise 5, b) is bijective (use c) and d) by considering an exact sequence A(J)→A(I)→M→0)A^{(J)}\rightarrow A^{(I)}\rightarrow M\rightarrow 0).

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