Bourbaki

Proposition 3

Tag 00A9, permanent. Cite it as [Bourbaki, Tag 00A9].

Algebra, VIII, p. 153, § 9. Radical

a) A semisimple module is without radical.

b) A module is semisimple and finitely generated if and only if it is without radical and Artinian.

By definition, the radical of a simple module is reduced to 0. If the module M is semisimple, then it is the direct sum of a family (Si)i∈I(S_i)_{i\in I} of simple submodules, and we have R(M)=⨁i∈IR(Si)\mathfrak{R}(M) =\bigoplus_{i\in I}\mathfrak{R}(S_i) by Corollary 2 of Proposition 1 above, hence R(M)=0\mathfrak{R}(M) = 0.

If, moreover, M is finitely generated, then it is Artinian by Proposition 10 of VIII, p. 71.

Conversely, suppose that M is Artinian and without radical. By VIII, p. 2 applied to the set of maximal submodules of M, there exists a finite family (Ni)i∈I(N_i)_{i\in I} of maximal submodules of M whose intersection is reduced to 0. Then M is isomorphic to a submodule of ⨁i∈I(M/Ni)\bigoplus_{i\in I}(M/N_i). Therefore, it is semisimple and has finite length, and is a fortiori finitely generated.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.