Bourbaki

Example 5

Tag 00AL, permanent. Cite it as [Bourbaki, Tag 00AL].

Algebra, VIII, p. 157, § 9. Radical

Let a\mathfrak{a} be a two-sided ideal of A. The a\mathfrak{a}-adic topology on A is the topology, compatible with the ring structure of A, for which the ideals an\mathfrak{a}^n (for n⩾1n\geqslant 1) form a fundamental system of neighborhoods of 0 (Gen. Top., III, §6, No. 3, p. 275, Example 3). Suppose that the ring A is Hausdorff and complete (Gen. Top., III, §6, No. 5, p. 276) for this topology; this is, for example, the case when the ideal a\mathfrak{a} is nilpotent. For every x∈ax\in \mathfrak{a}, the series ∑n=0∞(−x)n\sum^{\infty}_{n=0}(-x)^n is then convergent. Let yy be its sum. We have y−1=∑n=1∞(−x)n=−xyy-1 =\sum^{\infty}_{n=1}(-x)^n=-xy, hence (1+x)y=1(1 +x)y= 1. Likewise, we have y(1+x)=1y(1 +x) = 1, so 1+x1 +x is invertible. By Theorem 1, it follows that the ideal a\mathfrak{a} is contained in the radical of A.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 2023, Springer Nature. Not translated.