Bourbaki

Proposition 1

Tag 00E6, permanent. Cite it as [Bourbaki, Tag 00E6].

Algebra, VIII, p. 211, § 12. Tensor Products of Semisimple Modules

Let M1M_1 be an A1A_1-module and M2M_2 an A2A_2-module, neither reduced to 0. If the module M=M1⊗M2M = M_1\otimes M_2 over the ring A=A1⊗A2A = A_1\otimes A_2 is simple (resp. isotypical, semisimple), then the A1A_1-module M1M_1 and the A2A_2-module M2M_2 are simple (resp. isotypical, semisimple).

Suppose that M is a semisimple A-module. Let N1N_1 be an A1A_1-submodule of M1M_1. Denote the canonical image of N1⊗M2N_1\otimes M_2 in the A-module M by N. By Corollary 2 of VIII, p. 56, there exists an A-linear projector pp in M with image N. By assumption, we have M2≠0M_2\not= 0; we can therefore choose an element mm of M2M_2 and a linear form φ\varphi on the K-vector space M2M_2 such that φ(m)=1\varphi (m) = 1 (II, §7, No. 5, p. 302, Corollary 2). Let uu be the mapping from M1M_1 to M defined by u(m1)=m1⊗mu(m_1) =m_1\otimes m, and let vv be the K-linear mapping from M to M1M_1 characterized by v(m1⊗m2)=φ(m2)m1v(m_1\otimes m_2) =\varphi (m_2)m_1. Set q=v∘p∘uq=v\circ p\circ u. The mapping q:M1→M1q: M_1\rightarrow M_1 is A1A_1-linear, its image is contained in N1N_1, and we have q(n)=nq(n) =n for every n∈N1n\in N_1. Consequently, qq is a projector in M1M_1 with image N1N_1. We have proved that M1M_1 is a semisimple A1A_1-module (VIII, p. 56, Corollary 2).

Suppose that M is simple and that M1M_1 is the direct sum of two A1A_1-submodules M1′M'_1 and M1′′M''_1. Set M′=M1′⊗M2M'= M'_1\otimes M_2 and M′′=M1′′⊗M2M''= M''_1\otimes M_2; then M is the direct sum of the A-submodules M′M' and M′′M''. Since M is simple, M′M' or M′′M'' must be reduced to 0; as we have M2≠0M_2\not= 0 by assumption, we have M1′=0M'_1= 0 or M1′′=0M''_1= 0 (II, §3, No. 7, p. 256, Corollary 2). This proves that M1M_1 is a simple A1A_1-module.

Now suppose that M is an isotypical A-module. Let S and T be simple A1A_1-submodules of M1M_1. The A-modules S⊗M2S\otimes M_2 and T⊗M2T\otimes M_2 can then be identified with nonzero submodules of M. They are therefore isotypical of the same type as M. By Remark VIII, p. 61, there exists a nonzero A-linear mapping f:S⊗M2→T⊗M2f: S\otimes M_2\rightarrow T\otimes M_2. The mapping ff is, in particular, A1A_1-linear. Since the A1A_1-modules S⊗M2S\otimes M_2 and T⊗M2T\otimes M_2 are nonzero and isotypical of type S and T, respectively, S and T are isomorphic. This proves that M1M_1 is an isotypical A1A_1-module.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.