Bourbaki

Proposition 8

Tag 00IW, permanent. Cite it as [Bourbaki, Tag 00IW].

Algebra, VIII, p. 303, § 16. Other Descriptions of the Brauer Group

Let H be a subgroup of G of finite index. The endomorphism CorHG∘^G_H\circ ResHG^G_H of the group H2(G,F)H^2(G,F) coincides with multiplication by the index (G : H).

Let α\alpha be an element of H2(G,F)H^2(G,F), and let cc be an element of Z2(G,F)Z^2(G,F) representing α\alpha. The element CorHG∘^G_H\circ ResHG(α)^G_H(\alpha ) is the class of the cocycle whose value in (g1,g2)∈G2(g_1, g_2)\in G^2 is given by the expression

∏x∈H\Gs(x)−1c(s(x)g1s(x⋅g1)−1,s(x⋅g1)g2s(x⋅g1g2)−1) \prod_{x\in H\backslash G}^{s(x)^{-1}}c(s(x)g_1s(x\cdot g_1)^{-1}, s(x\cdot g_1)g_2s(x\cdot g_1g_2)^{-1})
=∏x∈H\Gc(g1s(x⋅g1)−1,s(x⋅g1)g2s(x⋅g1g2)−1) =\prod_{x\in H\backslash G}c(g_1s(x\cdot g_1)^{-1}, s(x\cdot g_1)g_2s(x\cdot g_1g_2)^{-1})
×∏x∈H\G(c(s(x)−1,s(x)g1g2s(x⋅g1g2)−1)−1c(s(x)−1,s(x)g1s(x⋅g1)−1)) \times \prod_{x\in H\backslash G}(c(s(x)^{-1}, s(x)g_1g_2s(x\cdot g_1g_2)^{-1})^{-1}c(s(x)^{-1}, s(x)g_1s(x\cdot g_1)^{-1}))
=∏x∈H\Gg1c(s(x⋅g1)−1,s(x⋅g1)g2s(x⋅g1g2)−1) =\prod_{x\in H\backslash G}^{g_1}c(s(x\cdot g_1)^{-1}, s(x\cdot g_1)g_2s(x\cdot g_1g_2)^{-1})
×∏x∈H\Gc(g1,g2s(x⋅g1g2)−1)c(g1,s(x⋅g1)−1)−1 \times \prod_{x\in H\backslash G}c(g_1, g_2s(x\cdot g_1g_2)^{-1})c(g_1, s(x\cdot g_1)^{-1})^{-1}
×∏x∈H\G(c(s(x)−1,s(x)g1g2s(x⋅g1g2)−1)−1c(s(x)−1,s(x)g1s(x⋅g1)−1)) \times \prod_{x\in H\backslash G}(c(s(x)^{-1}, s(x)g_1g_2s(x\cdot g_1g_2)^{-1})^{-1}c(s(x)^{-1}, s(x)g_1s(x\cdot g_1)^{-1}))
=∏x∈H\Gc(g1,g2s(x⋅g1g2)−1)c(g1,s(x⋅g1)−1)−1=\prod_{x\in H\backslash G}c(g_1, g_2s(x\cdot g_1g_2)^{-1})c(g_1, s(x\cdot g_1)^{-1})^{-1}
×∏x∈H\Gg1c(s(x)−1,s(x)g2s(xg2)−1) \times \prod_{x\in H\backslash G}^{g_1}c(s(x)^{-1}, s(x)g_2s(xg_2)^{-1})
×∏x∈H\G(c(s(x)−1,s(x)g1g2s(x⋅g1g2)−1)−1c(s(x)−1,s(x)g1s(x⋅g1)−1)) \times \prod_{x\in H\backslash G}(c(s(x)^{-1}, s(x)g_1g_2s(x\cdot g_1g_2)^{-1})^{-1}c(s(x)^{-1}, s(x)g_1s(x\cdot g_1)^{-1}))

The first equality comes from the cocycle relation (VIII, p. 295, formula (7)) applied to the elements

s(x)−1,s(x)g1s(x⋅g1)−1s(x)^{-1},s(x)g_1s(x\cdot g_1)^{-1}, and s(x⋅g1)g2s(x⋅g1g2)−1s(x\cdot g_1)g_2s(x\cdot g_1g_2)^{-1};

the second is obtained by applying the cocycle relation to the elements

g1,s(x⋅g1)−1g_1,s(x\cdot g_1)^{-1}, and s(x⋅g1)g2s(x⋅g1g2)−1s(x\cdot g_1)g_2s(x\cdot g_1g_2)^{-1}.

By removing a coboundary, we obtain that CorHG∘^G_H\circ ResHG(α)^G_H(\alpha ) is the class of the cocycle whose value in (g1,g2)∈G2(g_1, g_2)\in G^2 is given by the expression

∏x∈H\Gc(g1,g2s(x⋅g1g2)−1)c(g1,s(x⋅g1)−1)−1 \prod_{x\in H\backslash G}c(g_1, g_2s(x\cdot g_1g_2)^{-1})c(g_1, s(x\cdot g_1)^{-1})^{-1}
=∏x∈H\Gg1c(g2,s(x⋅g1g2)−1)−1c(g1g2,s(x⋅g1g2)−1)c(g1,g2) =\prod_{x\in H\backslash G}^{g_1}c(g_2, s(x\cdot g_1g_2)^{-1})^{-1}c(g_1g_2, s(x\cdot g_1g_2)^{-1})c(g_1, g_2)
×∏x∈H\Gc(g1,s(x⋅g1)−1)−1 \times \prod_{x\in H\backslash G}c(g_1, s(x\cdot g_1)^{-1})^{-1}
=∏x∈H\Gg1c(g2,s(x⋅g2)−1)−1c(g1g2,s(x⋅g1g2)−1)c(g1,s(x⋅g1)−1)−1 =\prod_{x\in H\backslash G}^{g_1}c(g_2, s(x\cdot g_2)^{-1})^{-1}c(g_1g_2, s(x\cdot g_1g_2)^{-1})c(g_1, s(x\cdot g_1)^{-1})^{-1}
×c(g1,g2)(G:H) \times c(g_1, g_2)^{(G:H)}

which proves the result.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed edition, 2023, Springer Nature. Not translated.