Bourbaki

Corollary 2

Tag 00R0, permanent. Cite it as [Bourbaki, Tag 00R0].

Algebra, VIII, p. 68, § 4. Semisimple Modules

Let M be an A-module. The following two conditions are equivalent:

(i) Every submodule of M admits a unique supplementary submodule.

(ii) The module M is the direct sum of a family (Si)i∈I(S_i)_{i\in I} of simple, pairwise nonisomorphic modules.

Suppose that M satisfies these conditions. Then, for every submodule N of M, there exists a unique subset J of I such that we have N=⨁j∈JSjN =\bigoplus_{j\in J}S_j and every simple submodule of M is equal to one of the SiS_i.

Conditions (i) and (ii) both imply that M is semisimple.

Suppose that condition (i) is satisfied. Let λ∈S\lambda \in \mathscr{S}. By the equivalence of (i) and (iii) in Corollary 1, every submodule of MλM_{\lambda} is zero or equal to MλM_{\lambda}. Consequently, MλM_{\lambda} is zero or simple, and (ii) follows from the fact that M is the direct sum of the family (Mλ)λ∈S(M_{\lambda})_{\lambda\in\mathscr{S}}.

Conversely, if condition (ii) is satisfied, then MλM_{\lambda} is zero or simple for every λ∈S\lambda \in \mathscr{S}. If N is a submodule of M, then N∩MλN\cap M_{\lambda} is equal to 0 or MλM_{\lambda} for every λ∈S\lambda \in \mathscr{S}. Since we have N=⨁λ∈S(N∩Mλ)N =\bigoplus_{\lambda\in\mathscr{S}}(N\cap M_{\lambda}) (VIII, p. 66, Corollary), the submodule N has property (iii) of Corollary 1 and therefore admits a unique supplementary submodule in M. This proves that (ii) implies (i), as well as the last assertions of the corollary.

Let M be an A-module and S a simple A-module. Denote the opposite ring of the field EndA(S)_A(S) by D, and view S as an (A(A, D)-bimodule. Then HomA(S,M)_A(S,M) is a left vector space over D, and HomA(M,S)_A(M,S) is a right vector space over D. The dual of the left D-vector space HomA(S,M)_A(S,M) is a right vector space over D (II, §2, No. 3, p. 232, Definition 2). For every u∈u\in HomA(M,S)_A(M,S), the mapping h(u):v↦u∘vh(u) :v\mapsto u\circ v from HomA(S,M)_A(S,M) to HomA(S,S)=D_A(S,S) = D is a linear form on the left D-vector space HomA(S,M)_A(S,M).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.