Bourbaki

Exercise 6, § 5

Tag 011Y, permanent. Cite it as [Bourbaki, Tag 011Y].

Lie Groups and Lie Algebras, VII, 64

Bourbaki marks this one as harder than the rest.

Let g\mathfrak{g} be a semi-simple subalgebra of gl\mathfrak{g}\mathfrak{l}(V), T(V)=⨁n=0∞Tn(V)\mathbf{T}(V) =\bigoplus_{n=0}^{\infty}\mathbf{T}^n(V) the

tensor algebra of V,T(V)gV,\mathbf{T}(V)^{\mathfrak{g}} the set of elements of T(V)\mathbf{T}(V) invariant under g\mathfrak{g} (cf. Chap. III, App.) and g‾\overline{\mathfrak{g}} the set of u∈gl(V)u\in \mathfrak{g}\mathfrak{l}(V) such that u.x=0u.x= 0 for all x∈T(V)gx\in \mathbf{T}(V)^{\mathfrak{g}}. We are going to show that g‾=g\overline{\mathfrak{g}}=\mathfrak{g}.

a) Show that the representation of g\mathfrak{g} on the dual V∗V^* of V is isomorphic to its representation on ⋀p−1V\bigwedge^{p-1}V, where p=p= dim V (use the fact that g\mathfrak{g} is contained in sl(V)\mathfrak{s}\mathfrak{l}(V)). Deduce that every element of Tn,m=Tn(V)⊗Tm(V∗)\mathbf{T}_{n,m}=\mathbf{T}^n(V)\otimes \mathbf{T}^m(V^*) invariant under g\mathfrak{g} is invariant under g‾\overline{\mathfrak{g}}, and that g‾\overline{\mathfrak{g}} is algebraic (Exerc. 5).

b) Let W be a vector subspace of one of the Tn,m\mathbf{T}_{n,m}. Assume that W is stable under g\mathfrak{g}. Show that W is stable under g‾\overline{\mathfrak{g}} (if e1,...,ere_1, . . . , e_r is a basis of W, remark that e1∧⋯∧ere_1\wedge \cdots \wedge e_r is invariant under g\mathfrak{g}, and hence under g‾\overline{\mathfrak{g}}).

Deduce that g\mathfrak{g} is an ideal of g‾\overline{\mathfrak{g}}, and that g‾/g\overline{\mathfrak{g}}/\mathfrak{g} is commutative (cf. proof of Prop. 4). We have g‾=g×c\overline{\mathfrak{g}}=\mathfrak{g}\times \mathfrak{c}, where c\mathfrak{c} is the centre of g‾\overline{\mathfrak{g}}.

c) Let R be the associative subalgebra of gl(V)\mathfrak{g}\mathfrak{l}(V) generated by 1 and g\mathfrak{g}. Show that c\mathfrak{c} is contained in the centre of R (remark that g‾\overline{\mathfrak{g}} is contained in the bicommutant of R, which is equal to R). Deduce that the elements of c\mathfrak{c} are semi-simple.

d) Let x∈cx\in \mathfrak{c}. Show that the replicas of xx belong to c\mathfrak{c} (Chap. I, §5, Exerc. 14). Show that Tr(sxsx) =0= 0 for all s∈gs\in \mathfrak{g}; deduce that Tr(sxsx) =0= 0 for all s∈g‾s\in \overline{\mathfrak{g}}, and hence that xx is nilpotent (loc. cit).

e) Show that c=0\mathfrak{c}= 0 and g‾=g\overline{\mathfrak{g}}=\mathfrak{g} by combining c) and d).

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