Bourbaki

Proposition 1

Tag 0155, permanent. Cite it as [Bourbaki, Tag 0155].

Lie Groups and Lie Algebras, chapter VIII, § 8. Symmetric invariants

Let Sm(h∗)WS^m(\mathfrak{h}^*)^W be the set of elements of Sm(h∗)S^m(\mathfrak{h}^*) invariant under W. Then prm(ψ(k[P]W))=Sm(h∗)W_m(\psi (k[P]^W)) =\mathbf{S}^m(\mathfrak{h}^*)^W.

It is clear from the preceding that prm(ψ(k[P]W))⊂Sm(h∗)W_m(\psi (k[P]^W))\subset \mathbf{S}^m(\mathfrak{h}^*)^W. Every element of Sm(h∗)\mathbf{S}^m(\mathfrak{h}^*) is a kk-linear combination of elements of the form

prm_m(exp λ\lambda ) == (prm∘ψ_m\circ \psi )(eλ)(e^{\lambda})

where λ∈P\lambda \in P (Lemma 1). Hence every element of Sm(h∗)W\mathbf{S}^m(\mathfrak{h}^*)^W is a linear combination of elements of the form

∑w∈Ww\sum_{w\in W}w((prm∘ψ_m\circ \psi )(eλ)(e^{\lambda})) == (prm∘ψ_m\circ \psi )(∑w∈Ww(eλ))(\sum_{w\in W}w(e^{\lambda})),

each of which belongs to prm(ψ(k[P]W))_m(\psi (k[P]^W)).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.