Bourbaki

Proposition 3

Tag 01FB, permanent. Cite it as [Bourbaki, Tag 01FB].

Lie Groups and Lie Algebras, chapter IX, § 6. Integration on compact Lie groups

Let ωg,ωt,ωG/T\omega_{\mathfrak{g}},\omega_{\mathfrak{t}},\omega_{G/T} be invariant differential forms on g,t\mathfrak{g},\mathfrak{t}, G/TG/T, respectively, of respective degrees n,r,n−rn, r, n-r. If ωg=ωG/T∩ωt\omega_{\mathfrak{g}}=\omega_{G/T}\cap \omega_{\mathfrak{t}}, we have

ψ∗ωg=ωG/T∧πgωt \psi^*\omega_{\mathfrak{g}}=\omega_{G/T}\wedge \pi_{\mathfrak{g}}\omega_{\mathfrak{t}}

where πg\pi_{\mathfrak{g}} is the function on t\mathfrak{t} defined by πg(x)=∏α∈R(G,T)δ(α)(x)\pi_{\mathfrak{g}}(x) =\prod_{\alpha\in R(G,T)}\delta (\alpha )(x).

Denote by ωG\omega_G (resp. ωT\omega_T) the invariant differential form of maximum degree on G (resp. T) that coincides with ωg\omega_{\mathfrak{g}} (resp. ωt\omega_{\mathfrak{t}}) at the origin. Consider the commutative diagram

(G/T)×t⟶ψg (G/T)\times \mathfrak{t}\longrightarrow^{\psi}\mathfrak{g}

(Id,expT_T) expG_G.

(G/T)×T⟶f(G/T)\times T\longrightarrow^f G

In view of Prop. 1 of no. 2 and the relation expT∗ωT=ωt^*_T\omega_T=\omega_{\mathfrak{t}}, we deduce the equality

ψ∗\psi^*expG∗ωG=ωG/T∧δgωt^*_G\omega_G=\omega_{G/T}\wedge \delta_{\mathfrak{g}}\omega_{\mathfrak{t}}.

By Prop. 2,ψ∗2,\psi^*expG∗ωG=(ψ∗λg)ψ∗ωg^*_G\omega_G= (\psi^*\lambda_{\mathfrak{g}})\psi^*\omega_{\mathfrak{g}}. Since the function λg\lambda_{\mathfrak{g}} is invariant under Ad(G), we have (ψ∗λg)(g‾,x)=λg(x)=δg(x)πg(x)(\psi^*\lambda_{\mathfrak{g}})(\overline{g}, x) =\lambda_{\mathfrak{g}}(x) =\frac{\delta_{\mathfrak{g}}(x)}{\pi_{\mathfrak{g}}(x)} for g‾∈G/T,x∈t\overline{g}\in G/T, x\in \mathfrak{t}.

It follows that the forms ψ∗ωG(g‾,x)\psi^*\omega_G(\overline{g}, x) and ωG/T(g‾)∧πg(x)ωt(x)\omega_{G/T}(\overline{g})\wedge \pi_{\mathfrak{g}}(x)\omega_{\mathfrak{t}}(x) coincide where δg(x)\delta_{\mathfrak{g}}(x) is non-zero, that is on the dense open subset (G/T)×tr(G/T)\times \mathfrak{t}_r; thus, they are equal, hence the proposition.

Choose invariant differential forms ωG\omega_G on G and ωT\omega_T on T, of maximum degree, such that ∣ωG∣=dg|\omega_G|=dg and ∣ωT∣=dt|\omega_T|=dt; denote by ωg\omega_{\mathfrak{g}} (resp. ωt\omega_{\mathfrak{t}}) the translation-invariant differential form on g\mathfrak{g} (resp. t\mathfrak{t}) that coincides with ωG(e)\omega_G(e) (resp. ωT(e)\omega_T(e)) at the origin, and dzdz (resp. dxdx) the Haar measure ∣ωg∣|\omega_{\mathfrak{g}}| (resp. ∣ωt∣|\omega_{\mathfrak{t}}|). Reasoning as in no. 2, mutatis mutandis, gives the following proposition:

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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