Bourbaki

Proposition 1

Tag 01EY, permanent. Cite it as [Bourbaki, Tag 01EY].

Lie Groups and Lie Algebras, chapter IX, § 6. Integration on compact Lie groups

Let ωG,ωG/T\omega_G, \omega_{G/T} and ωT\omega_T be invariant differential forms on G,G/TG,G/T and T, respectively, of respective degrees n,n−rn, n-r and rr. If ωG=\omega_G= ωG/T∩ωT\omega_{G/T}\cap \omega_T, then

f∗(ωG)=ωG/T∧δGωT f^*(\omega_G) =\omega_{G/T}\wedge \delta_G\omega_T

Clearly we can assume that ωG/T\omega_{G/T} and ωT\omega_T are non-zero; then the differential form (u,t)→ωG/T(u)∧ωT(t)(u, t) \rightarrow \omega_{G/T}(u)\wedge \omega_T(t) on (G/T)×T(G/T)\times T is of degree nn and everywhere non-zero; hence there exists a numerical function δ\delta on (G/T)×T(G/T)\times T such that

f∗(ωG)(u,t)=δ(u,t)ωG/T(u)∧ωT(t) f^*(\omega_G)(u, t) =\delta (u, t)\omega_{G/T}(u)\wedge \omega_T(t)

Observe now that, for h∈G,u∈G/T,t∈h\in G,u\in G/T,t\in T, we have f(h.u,t)=f(h.u, t) = (Int hh)f(u,t)f(u, t); since ωG\omega_G is invariant under inner automorphisms, it follows immediately that δ(h.u,t)=δ(u,t)\delta (h.u, t) =\delta (u, t), so δ(u,t)=δ(e‾,t)\delta (u, t) =\delta (\overline{e}, t).

Denote by p:g→g/tp:\mathfrak{g}\rightarrow \mathfrak{g}/\mathfrak{t} the quotient map and by φ:g/t→g\varphi :\mathfrak{g}/\mathfrak{t}\rightarrow \mathfrak{g} the map defined by

φ(p(X))=\varphi (p(X)) = (Ad t−1t^{-1})X−XX-X for X∈gX\in \mathfrak{g}; recall (§5, no. 4, Lemma 4) that the tangent map

T(e,t)(f):Te(G/T)×Tt(T)→Tt(G) T_{(e,t)}(f) : T_e(G/T)\times T_t(T)\rightarrow T_t(G)

takes (z,tH)(z, tH) to t(φ(z)+H)t(\varphi (z) +H) for z∈g/t,H∈tz\in \mathfrak{g}/\mathfrak{t}, H\in \mathfrak{t}.

Let z1,...,zn−rz_1, . . . , z_{n-r} be elements of g/t,H1,...,Hr\mathfrak{g}/\mathfrak{t},H_1, . . . , H_r elements of t\mathfrak{t}. Then

f∗ωG(e‾,t)(z1,...,zn−r,tH1,...,tHr) f^*\omega_G(\overline{e}, t)(z_1, . . . , z_{n-r}, tH_1, . . . , tH_r)

=ωG(t)(tφ(z1),...,tφ(zn−r),tH1,...,tHr)=\omega_G(t)(t\varphi (z_1), . . . , t\varphi (z_{n-r}), tH_1, . . . , tH_r) by the calculation of T(e‾,t)(f)T_{(\overline{e},t)}(f)

=ωG(e)(φ(z1),...,φ(zn−r),H1,...,Hr)=\omega_G(e)(\varphi (z_1), . . . , \varphi (z_{n-r}), H_1, . . . , H_r) since ωG\omega_G is invariant

=ωG/T(e‾)(pφ(z1),...,pφ(zn−r)).ωT(e)(H1,...,Hr)=\omega_{G/T}(\overline{e})(p\varphi (z_1), . . . , p\varphi (z_{n-r})).\omega_T(e)(H_1, . . . , H_r) (no.1.1, Lemma 1)

= det(pφp\varphi )ωG/T(e‾)(z1,...,zn−r).ωT(e)(H1,...,Hr)\omega_{G/T}(\overline{e})(z_1, . . . , z_{n-r}).\omega_T(e)(H_1, . . . , H_r)

=δG(t)ωG/T(e‾)(z1,...,zn−r).ωT(t)(tH1,...,tHr) =\delta_G(t)\omega_{G/T}(\overline{e})(z_1, . . . , z_{n-r}).\omega_T(t)(tH_1, . . . , tH_r)

since ωT\omega_T is invariant

=δG(t)(ωG/T∧ωT)(e‾,t)(z1,...,zn−r,tH1,...,tHr) =\delta_G(t)(\omega_{G/T}\wedge \omega_T)(\overline{e}, t)(z_1, . . . , z_{n-r}, tH_1, . . . , tH_r)

so f∗ωG(e‾,t)=δG(t)(ωG/T∧ωT)(e‾,t)f^*\omega_G(\overline{e}, t) =\delta_G(t)(\omega_{G/T}\wedge \omega_T)(\overline{e}, t); thus, δ(e‾,t)=δG(t)\delta (\overline{e}, t) =\delta_G(t), hence the proposition.

Give the manifolds G,TG,T and G/TG/T the orientations defined by the forms ωG,ωT\omega_G, \omega_T and ωG/T\omega_{G/T}, respectively. These forms define invariant measures on G,TG,T and G/TG/T (Chap. III, §3, no. 16, Props. 55 and 56), also denoted by ωG,ωT\omega_G, \omega_T and ωG/T\omega_{G/T}.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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