Let A and B be topological spaces and let u:A→B be a continuous mapping.
a) Let G1 and G2 be presheaves on B and let γ:G1→G2 be a morphism of presheaves. Let moreover F be a sheaf on A and φ:G2→u∗F a morphism of presheaves. One has the equality
(φ∘γ)♯=φ♯∘u∗(γ)(11)
b) Let F1,F2 be sheaves on A and let G be a presheaf on B. Let φ:F1→F2 be a morphism of sheaves and let γ:G→ u∗F1 be a morphism of presheaves. One has the relation
(u∗(φ)∘γ)♯=φ∘γ♯
a) By definition of φ♯ and Remark 2 of I, p. 60, one has
φ∘γ=u∗(φ♯)∘βG2∘γ=u∗(φ♯)∘u∗u∗(γ)∘βG1
Consequently, φ∘γ=u∗(φ♯∘u∗(γ))∘βG1, whence relation (11).
b) By definition of γ♯, one has
u∗(φ)∘γ=u∗(φ)∘u∗(γ♯)∘βG=u∗(φ∘γ♯)∘βG
whence the announced relation, having regard to the definition of (u∗(φ)∘γ)♯.
Put αF = Idu∗(F)♯; it is the unique sheaf morphism ρ:u∗(u∗(F))→F such that
Idu∗(F)=u∗(ρ)∘βu∗(F).
Relation (11), applied to G2=u∗(F) and to the morphism φ= Idu∗(F), yields for every presheaf morphism γ:G→u∗(F) the factorization
γ♯=αF∘u∗(γ)
It then follows from proposition 4 that for every sheaf morphism ψ of u∗(G) into F,ψ♭ is the unique morphism φ:G→u∗(F) such that ψ=αF∘u∗(φ).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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