Bourbaki

Proposition 10

Tag 01SQ, permanent. Cite it as [Bourbaki, Tag 01SQ].

Topologie algébrique, chapter I, § 6. Espaces simplement connexes

Let X be a nonempty connected topological space, let G be a discrete group operating continuously on the left in X, and let M be a subset of X such that G⋅M=XG\cdot M = X. One of the two following hypotheses is made:

(i) The set M is open;

(ii) The set M is closed and the covering (g⋅M)g∈G(g\cdot M)_{g\in G} of X is locally finite.

Let S be the set of elements g∈Gg\in G such that M∩g⋅M=∅̸M\cap g\cdot M=\not\emptyset, let T be the set of pairs (s,t)∈S×S(s, t)\in S\times S such that M∩s⋅M∩st⋅M=∅̸M\cap s\cdot M\cap st\cdot M=\not\emptyset. Let F be the group F(S,r)F(S,\mathbf{r}) defined by the generator set S and by the set r\mathbf{r} of relators str−1str^{-1} for r,s,t∈r, s, t\in S such that (s,t)∈(s, t)\in T and rr = stst; for s∈Ss\in S, let xsx_s denote the image of ss under the canonical mapping of S into F. There exists a unique group homomorphism φ:F→G\varphi : F\rightarrow G such that φ(xs)=s\varphi (x_s) =s for every s∈Ss\in S. It is surjective; it is an isomorphism if the space X is simply connected, or, more generally, if every covering of X which is trivializable over M is trivializable.

The homomorphism φ\varphi is surjective (I, p. 133, lemma 3). With the notation of this No.o^o, the covering Y of X is trivializable, since it is trivializable over M. By lemma 5, Y is connected. Consequently, p:Y→Xp: Y\rightarrow X is a homeomorphism and the group N is reduced to the identity element. Consequently, the homomorphism φ:F→G\varphi : F\rightarrow G is a group isomorphism.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.