Bourbaki

Example 4

Tag 01TB, permanent. Cite it as [Bourbaki, Tag 01TB].

Topologie algébrique, chapter II, § 3. Groupoïdes

Let G be a groupoid, let X be a set and let φ:X→\varphi : X\rightarrow Som(G) be a mapping. Define a graph G′G' in the following way. The set Som(G′') is the set X; for every pair (x,y)(x, y) of elements of X, the set Flx,y(G′)_{x,y}(G') is the set of triples (x,f,y)∈X×(x, f, y)\in X\times Fl(G) ×X\times X, where ff is an element of Flφ(x),φ(y)(G)_{\varphi(x),\varphi(y)}(G). Let x,y,zx,y,z be elements of X,f∈,f\in Flφ(x),φ(y)(G)_{\varphi(x),\varphi(y)}(G) and g∈g\in Flφ(y),φ(z)(G)_{\varphi(y),\varphi(z)}(G) arrows of G, and put (x,f,y)⋅(y,g,z)=(x,fg,z)(x, f, y)\cdot (y, g, z) = (x, f g, z). This defines a composition law in the graph G′G' which makes it a groupoid. It is called the inverse image groupoid of the groupoid G by the mapping φ\varphi and is denoted by φ∗(G)\varphi^*(G).

The pair (φ,ψ)(\varphi , \psi ), where ψ:\psi : Fl(φ∗(G)\varphi^*(G))→\rightarrow Fl(G) is the mapping defined by (x,f,y)↦f(x, f, y)\mapsto f is a groupoid morphism from φ∗(G)\varphi^*(G) into G, called the canonical morphism.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.