§ 3. Groupoids
1. Categories
Definition 1 01SZ
Let C be a quiver. Let J denote the set of pairs of arrows of C such that . A law of composition in C is a mapping Fl(C) such that, for every pair , the origin of the arrow is that of and its end that of .
Let C be a quiver endowed with a law of composition . Two arrows and such that are said to be composable; the arrow is called their composite, or their product, and is often denoted by , or even by .
For every vertex of C, the set = Fl, endowed with the mapping deduced from by passing to subsets, is a magma (A, I, p. 1, Def. 1).
One says that a family of arrows of C, indexed by a finite nonempty totally ordered set I, is composable if, for every pair of consecutive elements of I, the arrows and are composable. The product of such a family is defined by induction on the cardinal of I in the following way (cf. A, I, p. 3):
(i) if I has a single element ;
(ii) if I has at least two elements and if is the smallest element of I, one sets .
The law of composition is said to be associative if one has for every composable triple of arrows of C. When the law is associative, the product of a sequence of composable arrows, where is an integer , is denoted by .
Let be a vertex of C. One says that an arrow is an identity element of at if one has for every arrow with origin and for every arrow with end . There exists at most one identity element of at if and are two such elements, one has . When such an identity element exists, it is often denoted by ; it is then an identity element of the magma (A, I, p. 12).
Definition 2 01T0
A category is a quiver endowed with an associative law of composition for which there exists at each vertex an identity element.
Example 1 01T1
Let C be a quiver. Let Ch(C) denote the set of paths in C and Ch(C) Som(C) Ch(C) Som(C) the mappings which associate with a path its origin and its end. The quadruple (Som(C), Ch(C)) is a quiver. Endow it with the law of composition defined by juxtaposition of paths. This law of composition is associative; for every vertex of C, the constant loop of origin is an identity element at . Thus, is a category. It is said to be the category of paths of the quiver C.
Example 2 01T2
Let Σ be a Species of structures in a theory stronger than set theory and let be a term of satisfying conditions (MO), (MO) and (MO) of E, IV, p. 11. Let S be a set; suppose that every element of S is a pair , where is a set and a structure of species Σ on . Let F be the set of mappings such that there exist and in S such that is a -morphism of , endowed with the structure , into , endowed with the structure ; one then sets and . Endowed with the law of composition given by , the quiver is a category. In this context, the elements of S are rather called objects.
Let C be a category.
For every vertex of C, the set , endowed with the law of composition , is a monoid with identity element .
A map of C is said to be invertible if there exists a map of C such that and such that and are identity elements at and respectively. Such a map is unique (if and , one has ) and is called the inverse of ; the inverse of an invertible map is denoted by .
2. Functors
Definition 3 01T3
Let C and be categories. A functor from C into is a morphism of quivers such that for every pair of composable maps of C.
Let C and be categories and let be a functor. Let be an arrow of C its origin and its end; then, is an arrow of with origin and end .
Let C, be categories and let and be functors. Then, is a functor.
Let C be a category. Then the quiver morphism Id is a functor.
Let be a functor. In order that be an isomorphism, it is necessary and sufficient that the mappings Som( ) and Fl( ) be bijective.
Thus, if one calls a category structure on sets S and F the data of a quiver structure on these sets and of an associative composition law for which there exists at each vertex an identity element, one can take the functors as morphisms of the category structure (E, IV, p. 11).
3. Groupoids
Definition 4 01T4
A groupoid is a category each arrow of which is invertible.
Let G be a groupoid and let be a vertex of G. The monoid is a group, denoted by and called the isotropy group of G at .
Let be vertices of G and let be an arrow joining to . The mapping is a group isomorphism of onto , denoted by Int(). If and are composable arrows of G, one has Int() Int() Int() ; the inverse of the isomorphism Int() is the isomorphism Int().
A morphism of groupoids is a morphism of categories. Moreover, is an isomorphism of groupoids if and only if it is an isomorphism of categories.
Let be a morphism of groupoids. For every vertex of G, the mapping of into is a group homomorphism denoted by . In particular, one has .
For every arrow of G is the inverse of . If is an arrow of G joining a vertex to a vertex , one thus has, for every element , the relation Int()(Int()).
4. Orbits of a groupoid
Let G be a groupoid. The connected components of the underlying quiver of G are called the orbits of G. The set of the orbits of G is denoted by Orb(G); if is a morphism of groupoids, the mapping deduced from by passing to the connected components of the associated graphs is in general denoted by Orb( ) and called the mapping deduced from by passing to the orbits.
A groupoid which has exactly one orbit is said to be transitive. If G is a transitive groupoid, the groups , for Som(G), are isomorphic. One says that the groupoid G is simply transitive if it is transitive and if, moreover, the isotropy groups are all reduced to their identity element.
Proposition 1 01T5
Let G be a groupoid. The relation "there exists an arrow of G joining to " is an equivalence relation in the set of vertices of G whose equivalence classes are the orbits of G.
Let be vertices of G. One has ; if , ; if and , one has . This shows that the indicated relation is reflexive, symmetric and transitive; it is therefore an equivalence relation. The second assertion then results from the definition of the connected components of a quiver.
5. Examples of groupoids
1) Let G be a group. Let us denote by the quiver whose set of vertices is reduced to one element and whose set of arrows is G. Endowed with the law of composition induced by that of G is a groupoid, called the groupoid associated with the group G.
2) Let X be a set. Let G be the quiver , pr, pr; define a law of composition in G by putting , if are elements of X. This law is associative; for every , is the identity element at ; the inverse of the arrow is the arrow . The groupoid thus defined is called the groupoid of pairs of the set X. If X is not empty, it is simply transitive.
3) Let X and S be sets and let be a mapping. For , let . For and in S, let be the set of bijections from onto and let G be the sum of the sets . Let and be the mappings from G into S such that and for every element . The quadruple is a quiver. Endow it with the law of composition defined by if and , where are points of S. It is a groupoid; it is denoted by and called the groupoid of permutations of X relative to .
4) Let be a family of groupoids. Let us denote by G the product quiver of the family of underlying quivers; for each , let pr be the canonical quiver morphism. There exists a unique law of composition on G for which G is a groupoid and such that, for each , pr is a groupoid morphism. Let and be arrows of G; they are composable if and only if the arrows and are composable, for . One then has .
The quiver G, endowed with this law of composition, is called the product groupoid of the family . It satisfies the following universal property: for every groupoid and every family , where is a groupoid morphism of into , there exists a unique groupoid morphism such that pr for each .
5) Let be an inductive system of groupoids, indexed by a right filtering preordered set , the being groupoid morphisms. Let G be the quiver whose set of vertices is lim Som(G), whose set of arrows is lim Fl(G), the source and target mappings being the mappings lim and lim respectively. The laws of composition of the induce a law of composition on G which makes it a groupoid (cf. A, I, p. 114). The canonical mappings Som(G) Som(G) and Fl(G) Fl(G) define a groupoid morphism of into G. If are elements of I such that , one has . The groupoid G is called the inductive limit of the family of groupoids and is denoted by lim. It satisfies the following universal property: for every groupoid H and every family , where, for is a groupoid morphism, such that for every pair of elements of I such that , there exists a unique groupoid morphism such that .
For the existence of a groupoid satisfying this universal property when one does not suppose that the set I is right filtering, cf. II, p. 228, exerc. 3.
6. Subgroupoids
Definition 5 01T6
Let C be a category. A subcategory of C is a subquiver D of C satisfying the following conditions:
(i) For every vertex of D is an arrow of D;
(ii) For every composable pair of arrows of C belonging to D, the product is an arrow of D;
Let C be a category and let D be a subcategory of D; endowed with the law of composition deduced from that of C by passing to subsets, D is a category.
Every full subquiver of C is a subcategory of C. The intersection of a family of subcategories of C is a subcategory of C.
Definition 6 01T7
Let G be a groupoid. A subgroupoid of G is a subcategory H of G such that the inverse of every arrow of G belonging to H is an arrow of H.
Let G be a groupoid. Every subgroupoid of G is a groupoid. Every full subquiver of G is a subgroupoid of G. The intersection of a family of subgroupoids of G is a subgroupoid of G.
Let H be a subquiver of G. The intersection of the subgroupoids of G of which H is a subquiver is called the subgroupoid of G generated by H. The set of its vertices is equal to that of H and its orbits are the connected components of H.
Example 1 01T8
Let X be a set; let us denote by the groupoid of pairs of X (II, p. 163, Example 2). Let R be an equivalence relation on X. The subquiver of the groupoid whose set of vertices is X and whose set of arrows is the graph of the equivalence relation R is a subgroupoid of . Its orbits are the equivalence classes of the relation R.
Conversely, every subgroupoid of whose set of vertices is X is of this form.
Let X and S be sets and let S be a mapping. The mapping defines an equivalence relation in X (E, II, p. 41). One denotes by the subgroupoid of defined by this equivalence relation, and one calls it the groupoid of pairs of .
Example 2 01T9
Let G and be groupoids, let and be groupoid morphisms from G into . The equalizer of and cf. II, p. 153) is a subgroupoid of G.
Example 3 01TA
Let X be a set and Γ a group. Denote by the graph whose set of vertices is X, whose set of arrows is , the origin and end mappings being respectively pr and pr. Endowed with the composition law , it is a groupoid. It is moreover the groupoid deduced by transport of structure from the groupoid , product of the groupoid of pairs and of the groupoid associated with the group Γ (II, p. 163, example 1), by means of the bijection of onto .
Let be a right operation of the group Γ on X. The graph F of the mapping , that is to say the set of triples such that , is the set of arrows of a unique subgroupoid G of . The orbits of this groupoid are the orbits of Γ in X; if , the isotropy group of G at is the set of , where runs through the stabilizer of in Γ.
Conversely, every subgroupoid G of the groupoid such that the mapping (pr, pr) of Fl(G) into is a bijection is of this form.
Example 4 01TB
Let G be a groupoid, let X be a set and let Som(G) be a mapping. Define a graph in the following way. The set Som(G) is the set X; for every pair of elements of X, the set Fl is the set of triples Fl(G) , where is an element of Fl. Let be elements of X Fl and Fl arrows of G, and put . This defines a composition law in the graph which makes it a groupoid. It is called the inverse image groupoid of the groupoid G by the mapping and is denoted by .
The pair , where Fl() Fl(G) is the mapping defined by is a groupoid morphism from into G, called the canonical morphism.
Example 5 01TC
Let be a morphism of groupoids. Let H be the subquiver of G with set of vertices Som(G) and whose set of arrows consists of the Fl(G) such that is an identity element of . For every Som(G). For every Fl(H), , hence Fl(H). Further, if and are composable arrows of H, one has , hence is an arrow of H. This shows that H is a subgroupoid of G. It is called the kernel of and is denoted by Ker( ).
Example 6 01TD
Let be a morphism of groupoids. The quiver whose set of vertices is (Som(G)) and whose set of arrows is (Fl(G)) is not in general a subgroupoid of . This is nevertheless the case if the mapping Som( ) is injective (II, p. 225, exerc. 5).
7. Operations of a groupoid
Let G be a groupoid; let S denote the set of its vertices. Let X be a set and let be a mapping. A (right) operation of the groupoid G on the set X, relative to , is a morphism of groupoids from G into the groupoid of permutations of the set X relative to II, p. 163) which induces the identity on the set of vertices. In other words, consists, for each pair of points of S and for each arrow joining to , of a mapping , such that, for every pair of composable arrows of G,
and such that, for every is the identity of .
Let and be operations of the groupoid G on a set X, relative to a mapping . In order that one have , it is enough that there exist a subquiver H of G, generating G, such that for every Fl(H). In fact, the set of arrows of G such that is the set of arrows of a subgroupoid of G, with set of vertices S.
Let G be a groupoid with set of vertices S, let X be a set, let be a mapping, and let be an operation of G on X relative to . Let be the subquiver of whose set of vertices is X and whose set of arrows is the set of triples Fl(G) such that . It is a subgroupoid of .
Conversely, let Γ be a subgroupoid of ; suppose that the mapping of Fl(Γ) into Fl(G) is injective and that its image is the set of pairs such that . Then there exists a unique operation of the groupoid G on X such that .
The orbits of the groupoid are called the orbits of the operation of G on X. By definition, they are the equivalence classes of the relation in X defined by if and only if there exists Fl(G) such that .
Example 1 01TE
Let G be a group, and let be the groupoid associated with G (II, p. 163, Example 1). If X is a set, an operation (on the right) of the groupoid on X is nothing other than an operation (on the right) of the group G on X. Moreover, the orbits of the operation of coincide with those of the group G.
Example 2 01TF
Let be a groupoid. There exists a unique operation of G on the set S, relative to Id. It is given by if . The orbits for this operation are the orbits of G in the sense defined on p. 162.
Let G be a groupoid, let S be the set of its vertices, let X be a set, and let be a mapping. Let be an operation of G on X relative to . One says that the groupoid G operates without monodromy on X if, for every point and every element is the identity of . If the groupoid G is transitive, it is enough that this be so for one point of S.
Let be a point of S and suppose that one has Id for every . Let be a point of S belonging to the orbit of and let be an arrow of G joining to . For every , Int() is an element of ; hence one has Id, so that Id. Let be a point of S belonging to the orbit of and let be arrows of G joining to ; then is a loop at , whence Id and .
8. Normal Subgroupoids; Quotient Groupoids
Definition 7 01TG
Let G be a groupoid. One says that a subgroupoid H of G is normal if Som(H) = Som(G) and if for every pair of vertices of H and every arrow , one has Int().
Let G be a groupoid and let H be a subgroupoid of G whose set of vertices is equal to Som(G). To verify that H is distinguished, it is enough to prove that for every Som(G), every Som(G) and every . In fact, if this is so, one also has for every arrow , that is, , and consequently .
Let G be a groupoid and let H be a distinguished subgroupoid of G. For every vertex of G, the subgroup of is a distinguished subgroup of .
Let be a morphism of groupoids. The kernel of II, p. 166, example 5) is a distinguished subgroupoid of G. In fact, let be an arrow in G joining to and let Ker( ); then one has , whence the inclusion Ker( ) Ker( ).
Let G be a groupoid. The groupoid G and the subgroupoid of G whose set of arrows is the set of identity elements of G are distinguished subgroupoids of G. The intersection of a family of distinguished subgroupoids of G is a distinguished subgroupoid of G. In particular, for every subset Fl(G), there exists a smallest distinguished subgroupoid of G whose set of arrows contains F. It is called the distinguished subgroupoid generated by F.
Let H be a distinguished subgroupoid of G. Let be the equivalence relation in Fl(G) defined by if and only if there exist arrows and in Fl(H) such that . If and are arrows of G equivalent modulo , their origins (resp. their ends) belong to the same orbit of H. Put Fl(G) and denote by and the mappings of into Orb(H) deduced from and by passing to the quotients. Denote by the quiver (Orb(H)).
Lemma 01TH
Given composable arrows and of , one can choose representatives and of and in Fl(G) which are composable. The class modulo of the product does not depend on the choice of and .
Let and be arbitrary representatives of and in Fl(G). The end of and the origin of belong to one and the same orbit of H, hence can be joined by an arrow of H (II, p. 162, prop. 1). The arrows and are then representatives of and in F which are composable in G. This proves the first assertion.
Let now on the one hand, and on the other hand, be representatives of and which are composable in G. By hypothesis, there exist arrows in H such that one has and . Then one has and . Since H is a normal subgroupoid of G, the arrow is an arrow of H. The same is therefore true of the arrow , which proves that and are equivalent modulo .
By virtue of this lemma, there exists a unique law of composition in the quiver such that, for every pair of composable arrows, is the class modulo of the product , for every pair of composable arrows of G such that is the class of and that of . Endowed with this law of composition, is a groupoid. Let Som(G) Som(G) and Fl(G) Fl(G) be the canonical surjections. The pair is a morphism of groupoids of G into whose kernel is the normal subgroupoid H.
Definition 8 01TI
One says that is the quotient groupoid of G by H and that is the canonical morphism.
Remark 1 01TJ
The mapping Som() defines, by passing to quotients, a bijection of the set of orbits of G onto the set of orbits of . In particular, G is transitive if and only if is.
Remark 2 01TK
Let and be vertices of G. The mapping of into deduced from is surjective. Let in fact be an arrow of joining to ; it is the class modulo of an arrow of G. The origin of belongs to the orbit of in H; hence there exists an arrow in H joining to . Analogously, there exists an arrow in H joining to . Then is an element of whose class modulo is .
Proposition 2 01TL
Let be a vertex of G. The group homomorphism deduced from by passing to the isotropy groups is surjective; its kernel is .
The homomorphism is surjective by virtue of the preceding remark. Its kernel contains by construction of the groupoid . Let be an element of such that . This means that and are equivalent modulo ; there then exist arrows and of H such that . Necessarily, and belong to , whence .
Proposition 3 01TM
Let G be a groupoid, let H be a distinguished subgroupoid of G and let be the canonical morphism. Let be a groupoid morphism such that Ker( ). There exists a unique groupoid morphism such that .
One says that is the groupoid morphism deduced from by passing to the quotient.
The uniqueness of such a morphism is obvious, since the mappings Som() and Fl() are surjective.
Let and be vertices of G. If they are in the same orbit of H, there exists an arrow joining to in H, and one has . In particular, . Consequently, the mapping Som( ) defines, by passing to the quotient, a mapping Orb(H) Som(G). Let and be arrows in G. If and are equivalent modulo , there exist arrows and in H such that = . Consequently, since and are identity elements. The mapping Fl( ) therefore defines, by passing to the quotient, a mapping Fl(G) Fl(G).
Let and be composable arrows of G; let us denote by and their classes in Fl(G). One has .
The pair is a groupoid morphism from into and one has .
9. Groupoid of classes of paths of a graph
Let G be a graph. Let us denote by the category of paths of the underlying quiver of G (II, p. 160, example 1). Consider the finest equivalence relation in Ch(G) such that one has:
(i) For every pair of vertices of G and every arrow in G joining to , the paths and are equivalent modulo ;
(ii) If and are pairs of juxtaposed paths in G such that and , the paths and are equivalent modulo .
Two paths equivalent modulo have the same origin and the same end. The mappings and from Ch(G) into Som(G) define, by passing to the quotient, mappings and from Ch(G) into Som(G). Let us denote by the quiver (Som(G), Ch(G)). The pair formed by the identity mapping of Som(G) and the canonical projection of Ch(G) onto Ch(G) is a morphism of quivers from into . The juxtaposition of paths in Ch(G) defines, by passing to the quotients, a law of composition in .
Proposition 4 01TN
Endowed with this law of composition, is a groupoid.
By construction, one has the relation , for every pair of juxtaposed paths in G. Every arrow of is of the form , where is a path in G. It follows that the law of composition of is associative and that is an identity element at , for every vertex of . It remains to prove that every arrow of is invertible. Let be a path in G, and let us prove by induction on the length of that one has . This equality is true if is of length 0. If is of length , we may write , with of length 1 and of length . Then, and one has
by definition of the relation .
Applying this equality to the path , we see that . Thus, is invertible, with inverse .
The equivalence classes of the relation are called the path classes in the graph G; the groupoid is called the groupoid of path classes of the graph G. It has the same set of vertices as G, and its orbits are the connected components of the graph G.
Let us denote by the mapping which associates with an arrow of G the class of the path of G. The pair = (Id) is a morphism, called canonical, of quivers from G into . Its image generates ; for every arrow of G, one has .
Let G and be graphs, let be a graph morphism. Let us denote by and the canonical morphisms. If is a path in G, the class of the path depends only on the class of . Thus, by passing to equivalence classes, one defines a quiver morphism such that . It is a groupoid morphism.
Proposition 5 01TO
Let G be a graph; let us denote by the canonical quiver morphism of G into . Let be a quiver morphism of G into a groupoid such that for every arrow of G. Then there exists a unique groupoid morphism of into such that .
One defines a mapping Ch(G) Fl(G) by setting, for every path in G. For every pair of composable paths in G, one has . The mapping is compatible with the equivalence relation defined above, whence, by passing to the quotient, a mapping Ch(G) Fl(G). Let us then set (Som( )). It is a groupoid morphism of into such that .
Let be a groupoid morphism of into such that . The equalizer of and is a subgroupoid of which contains . Hence it is equal to , because is generated by , and one has .
Corollary 1 01TP
In a graph, every class of paths contains a unique path without retracing.
Let G be a graph. Let us denote by the canonical quiver morphism.
The existence, for every path of G, of an equivalent path without retracing is immediate by induction on the length of (cf. II, p. 157).
Let A be an orientation of G and let be the groupoid associated with the free group F(A) constructed on A (II, p. 163, Example 1). Let be the morphism of quivers from G into such that, for every is the element of F(A) and is the element of F(A). Let be the unique morphism of groupoids from into such that .
Let be paths without backtracking equivalent modulo . They have the same source and the same end. To prove that they are equal, it is enough to prove that the sequences and of their edges are equal. The image under of the common class of and is equal to and to . Now the terms of the sequences and belong to the subset of F(A) and two consecutive elements of these sequences are not inverses of one another. By A, I, p. 84, Prop. 7, these two sequences are equal. It follows that the sequences and are equal, and therefore that , whence uniqueness.
Corollary 2 01TQ
The canonical morphism from G into is injective.
This results immediately from Corollary 1.
Corollary 3 01TR
Let be a subgraph of G. The morphism from into deduced from the injection of into G is injective.
Let us denote by the inclusion morphism of into G and by the morphism from into deduced from it. The mappings Som() and Som() coincide. Moreover, if is a path without backtracking in , the path is a path without backtracking in G. The assertion therefore results from Corollary 1.
Corollary 4 01TS
A nonempty graph G is a tree if and only if the groupoid is simply transitive.
Let be a point of G. By Corollary 1, the following properties are equivalent:
(i) The isotropy group of at is reduced to the identity element;
(ii) The only loop in G with origin which is without backtracking is the constant loop with origin .
The groupoid is simply transitive if and only if it is transitive and has property (i) for every . The graph G is a tree if and only if it is connected and has property (ii) for every point . Since the orbits of are identified with the connected components of G, the corollary follows.
10. Free Groupoids
Definition 9 01TT
Let C be a quiver. The groupoid of classes of paths of the graph associated with C is called the free groupoid constructed on C, and is denoted by Grp(C).
The set of vertices of Grp(C) is equal to that of the vertices of C; the orbits of Grp(C) are the connected components of C.
Let C be a nonempty quiver. By Corollary 4, p. 174, the graph associated with C is a tree if and only if the free groupoid Grp(C) constructed on C is simply transitive.
The composite of the canonical quiver morphisms and is a quiver morphism from C into Grp(C) which is called the canonical morphism of C into Grp(C). Let us denote it by . For every vertex of C, one has . If is an arrow of C is the class of the path of . The morphism is injective (II, p. 174, Corollary 2) and its image generates the groupoid Grp(C).
Let be a quiver morphism. Let us denote by (resp. ) the canonical morphism of C into Grp(C) (resp. of into Grp(C)). The morphism is the unique groupoid morphism from Grp(C) into Grp(C) such that .
Proposition 6 01TU
Let C be a quiver, let G be a groupoid, and let be a quiver morphism from C into G. There exists a unique groupoid morphism from Grp(C) into G such that .
Let be the quiver morphism from into G such that for every vertex of C and for every arrow of C and every . One has . By Proposition 5, p. 173, there exists a morphism from Grp(C) into G such that . One then has . As in the proof of Prop. 5, the uniqueness of results from the fact that generates the groupoid Grp(C).
Under the hypotheses of Prop. 6, one sometimes says that is the groupoid morphism from Grp(C) into G extending the quiver morphism .
Example 01TV
Let C be a quiver having a unique vertex and let A be the set of its arrows. The groupoid Grp(C) is then the groupoid associated with the free group F(A) constructed on A. In fact, it has a unique vertex and it results immediately from Prop. 6 that the canonical mapping from A into Grp(C) deduced from the canonical morphism of C into Grp(C) satisfies the universal property of free groups (A, I, p. 85, Prop. 8).
11. Contraction of arrows of a groupoid
Let G be a groupoid and let F be a subset of the set of arrows of G. Let H be the normal subgroupoid of G generated by F. The groupoid is called the groupoid deduced from G by contraction of the set of arrows F and is denoted by . If denotes the canonical morphism from G into , one has and for every arrow .
This morphism satisfies the following universal property.
Proposition 7 01TW
For every groupoid morphism which maps every arrow belonging to F onto an identity element of , there exists a unique groupoid morphism such that .
The kernel of is a normal subgroupoid of G and the set of its arrows contains F. By definition, H is the smallest normal subgroupoid of G whose set of arrows contains F; it is therefore contained in the kernel of . The proposition then results from II, p. 170, Prop. 3.
Let us denote by Γ the subquiver of G whose set of vertices is Som(G) and whose set of arrows is F. The orbits of H are identified with the connected components of the quiver Γ. By definition of the quotient of a groupoid by a normal subgroupoid, the set of vertices of is identified with the set of connected components of Γ; in other words, it is the quotient set of Som(G) by the finest equivalence relation such that is equivalent to for every arrow .
The mapping induces, by passing to quotients, a bijection of the set of orbits of G onto the set of orbits of (II, p. 170, remark 1).
The purpose of this No is to calculate the homomorphisms induced by by passing to the isotropy groups, which amounts, according to prop. 2 (II, p. 170), to calculating the isotropy groups of the subgroupoid H.
Proposition 8 01TX
Let be the canonical morphism of the free groupoid Grp(Γ) into G extending the canonical injective morphism of Γ into G. Let be a vertex of G and let A be the orbit of in G. For every , let be an arrow of G joining to . The isotropy group is the distinguished subgroup of generated by the elements Int(), where runs through the set A and runs through the elements of Grp(Γ).
If and are vertices of G belonging to the same orbit, with , let us moreover fix an arrow of G joining to . For every point of G, let be the distinguished subgroup of generated by the elements Int(), where runs through the orbit of in G and runs through the group Grp(Γ). For every and every , one has . Let Som(G). One has (Grp(Γ)), by definition of . By definition of the groupoid H is an arrow of H for every arrow of Grp(Γ) ; consequently, (Grp(Γ)) is contained in . Since H is a distinguished subgroupoid of G, one then has
Int() Int() Int()
for every Som(G), and hence .
Let and be vertices of Γ. Put if and do not belong to the same connected component of Γ. In the contrary case, let and be classes of paths joining to in the quiver associated with Γ. Let be a vertex of G belonging to the orbit of and let be an element of Grp(Γ); in the group , we have the equality:
The arrow is the class of a loop at in the quiver Γ, hence belongs to , as does the arrow . Since belongs to and is a distinguished subgroup of , it follows that belongs to . Consequently, . By symmetry, we have . This implies that this set does not depend on the choice of and ; we denote it by .
Let N be the subquiver of G whose set of vertices is Som(G) and whose set of arrows joining to is equal to for every pair of vertices of G. It is a distinguished subgroupoid of G whose set of arrows contains F; hence H is a subgroupoid of N. In particular, , whence the equality.
Corollary 1 01TY
Suppose further that, for every arrow of F, we have . Then the origin and the end of every path in the quiver Γ coincide. Let be a vertex of G and let A be its orbit in G. For every element of F whose origin belongs to A, let us fix an arrow of G joining to and put Int() .
The group is then the distinguished subgroup of generated by the arrows .
By Prop. 8, the arrows are contained in the group . Let denote the smallest normal subgroup of containing them. By that proposition, it is enough to prove that, for every vertex of G belonging to A, every arrow joining to in G, and every element of Grp(Γ), Int() belongs to . Since the origin and the term of every element of F are equal, a loop at a vertex in the graph is of the form , where for every is an element of F with origin and . We have
Int().
Since , it follows that Int() belongs to .
Corollary 2 01TZ
If the graph associated with the quiver Γ is a forest, the homomorphism of into is bijective, for every vertex of G.
In fact, under this assumption, one has Grp(Γ) for every vertex of G (Corollary 1 of II, p. 173). It then follows from Proposition 8 that, for every vertex of G, the group reduces to the identity element.
12. Poincaré Group of a Graph
Let G be a graph. Let be a vertex of G; the isotropy group at of the groupoid Grp(G) is called the Poincaré group of G at and is denoted by . Let be a class of paths in G, and let be its origin and its term. The map Int() defined by is a group isomorphism. Let be a graph morphism. Let Grp(G) and Grp(H) denote the canonical morphisms. If denotes the unique groupoid morphism Grp(G) Grp(H) such that , the group homomorphism is denoted by .
Let G be a connected graph, let S be an orientation of G and let A be a maximal oriented tree of G (II, p. 157, prop. 1). Given vertices and of G, there exists a unique class of paths in the graph associated with A which joins to II, p. 174, cor. 4 of prop. 5). If , and are vertices of G, one has , these two classes of paths being equal to the unique class of paths joining to in .
Proposition 9 01U0
Let be a vertex of G. There exists a unique homomorphism of the free group F(S-Fl(A)) into such that
for - Fl(A). The homomorphism is a group isomorphism.
Let us denote by L the group F(S-Fl(A)). The existence and uniqueness of the homomorphism satisfying relations (1) follows from A, I, p. 85, prop. 8. Let be the groupoid associated with the group L (II, p. 163, example 1); let us denote by its unique vertex. There exists a unique groupoid morphism Grp(G) such that for every arrow S-Fl(A) and for every arrow Fl(A) (II, p. 173, prop. 5). For S-Fl(A), one has ; the homomorphism is therefore the identity isomorphism of the group L (A, I, p. 85, prop. 8). It follows that is injective.
Let be the groupoid deduced from by contraction of the arrows of A and let be the canonical groupoid morphism. It is surjective and the group homomorphism deduced from by passing to the isotropy groups is an isomorphism (II, p. 178, cor. 2 of prop. 8). Since the graph G is assumed connected and A is a maximal tree in it, the groupoid has a unique vertex (II, p. 176). Moreover, is generated by ; consequently, is generated by the loops , for , and the group is generated by the elements of the form , for S-Fl(A). The homomorphism is therefore surjective. Consequently, is surjective.
Remark 1 01U1
The homomorphism is the inverse isomorphism of .
Remark 2 01U2
There exists a unique homomorphism F(Fl(G)) defined by relations (1) for every Fl(G). It follows from proposition 8 that the homomorphism is surjective and that its kernel is the smallest normal subgroup of F(Fl(G)) containing the elements , for Fl(A), and the elements , for Fl(G).
Exercises
See the exercises for § 3.