Bourbaki

Proposition 4

Tag 01UD, permanent. Cite it as [Bourbaki, Tag 01UD].

Topologie algébrique, chapter II, § 4. Homotopies

The mapping Orb(α\alpha ):: Orb(G) →\rightarrow Orb(Coh(φ,ψ\varphi , \psi )) is surjective; its fibres are the connected components of the framework of the pair (φ,ψ)(\varphi , \psi ).

The morphism α\alpha is the composite of the morphisms α1:G→G1\alpha_1: G\rightarrow G_1, θ1:G1→\theta_1: G_1\rightarrow Grp(G1_1) and π:\pi : Grp(G1_1)→\rightarrow Coh(φ,ψ\varphi , \psi ). The mapping θ1\theta_1 induces a bijection of the set of connected components of the quiver G1G_1 onto the set of orbits of Grp(G1_1), and the mapping Orb(π\pi ):: Orb(Grp(G1_1))→\rightarrow Orb(Coh(φ,ψ\varphi , \psi )) is bijective (II, p. 170, remark 1). It is therefore enough to prove that the mapping of Orb(G) into π0(G1)\pi_0(G_1) deduced from α1\alpha_1 is surjective and that its fibres are the connected components of the framework of the pair (φ,ψ)(\varphi , \psi ). The surjectivity results from the fact that the mapping Som(α1\alpha_1) is the identity mapping. The equivalence relation in Som(G) defined by “aa and bb are in the same connected component of G1G_1” is generated by the relations “there exists an arrow of G joining aa to bb” and “there exists a vertex hh of H such that φ(h)=a\varphi (h) =a and ψ(h)=b\psi (h) =b”. This equivalence relation is compatible with the mapping of Som(G) into Orb(G), and the relation deduced from it in Orb(G) is generated by the relation “there exists an orbit η\eta of H such that Orb(φ\varphi )(η)=α(\eta ) =\alpha and Orb(ψ\psi )(η)=β(\eta ) =\beta”. It is therefore the relation “α\alpha and β\beta are in the same connected component of the framework of the pair (α,β)(\alpha , \beta )”.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.