Bourbaki

Proposition 18

Tag 01Y4, permanent. Cite it as [Bourbaki, Tag 01Y4].

Topologie algébrique, chapter III, § 2. Homotopie et chemins

Let X be a separated topological space. Let aa and bb be distinct points of X which belong to the same arcwise connected component of X. There exists an injective path joining aa to bb in X.

Let f:I→Xf:\mathbf{I}\rightarrow X be a path joining aa to bb in X. Let U\mathscr{U} be the set of open subsets U of ]0,1[]0,1[ such that f(x)=f(y)f(x) =f(y) for every connected component ]x,y[]x, y[ of U.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5-6, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.