Bourbaki

Corollary 1

Tag 023W, permanent. Cite it as [Bourbaki, Tag 023W].

Topologie algébrique, chapter IV, § 6. Espaces classifiants

Let X be a normal topological space, let ff be a continuous mapping of X into a topological space Z. Let A be a closed subspace of X, let U be a neighbourhood of A in X and let σ:U×\sigma : U\times I→Z\mathbf{I}\rightarrow Z be a homotopy whose term is the mapping f∣Uf|U. There exists a homotopy σ~:X×I→Z\widetilde{\sigma}: X\times \mathbf{I}\rightarrow Z whose term is the mapping ff and which coincides with σ\sigma in A×IA\times \mathbf{I}.

Put X′=XX'= X and let r:X×I→r: X\times \mathbf{I}\rightarrow Cyl(iUi_U) be the continuous mapping given by Prop. 1. With the notations introduced in the proof of this proposition, there exists a unique continuous mapping F: Cyl(iUi_U)→Z\rightarrow Z such that F(α(x,t))=σ(x,t)F(\alpha (x, t)) =\sigma (x, t) for (x,t)∈U×I(x, t)\in U\times \mathbf{I} and F(β(x))=f(x)F(\beta (x)) =f(x) for x∈x\in X (III, p. 238, Prop. 4). The mapping F∘r:X×I→F\circ r: X\times \mathbf{I}\rightarrow Z is a homotopy ; its term maps a point x∈x\in X to F(r(x,1))=F(β(x))=f(x)F(r(x,1)) = F(\beta (x)) =f(x). If (x,t)∈A×I(x, t)\in A\times \mathbf{I}, F(r(x,t))=F(α(x,t))=σ(x,t)F(r(x, t)) = F(\alpha (x, t)) =\sigma (x, t), therefore this homotopy coincides with σ\sigma on A×IA\times \mathbf{I}.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.