Lemma 3
Tag 0244, permanent. Cite it as [Bourbaki, Tag 0244].
Topologie algébrique, chapter IV, § 6. Espaces classifiants
Let B be a topological space and let be a locally trivial -fibered space. Every point of B possesses a neighbourhood V such that the -space is trivializable.
Let be a point of B; for every point of , there exists an open neighbourhood of in and a neighbourhood of in B such that E is trivializable over . There then exist an integer and, for every integer such that 1 , a point of such that the interval is contained in III, p. 272, lemma 4). Put . The fibered space E is trivializable over for every integer such that . Lemma 3 then follows from Lemma 2 by induction on .
Let us now prove the proposition. By lemma 3, there exists an open covering of B such that, for every , E is trivializable over . Since the space B is paracompact, we may suppose the covering locally finite (TG, IX, p. 49) and choose a covering of B where, for every , the set is closed in B and contained in (TG, IX, p. 49, prop. 4 and p. 48, cor. 1).
For every open subset U of B, let us denote by the set of -isomorphisms of onto which induce the identical mapping of onto . For every pair of open sets of B such that , let us denote by the mapping which, to a -isomorphism , associates the -isomorphism deduced from by passing to the subspaces. The pair is a sheaf on B (I, p. 45, example 4). To prove the proposition, it is enough to prove that the sheaf is soft (I, p. 64).
Let , let A be a closed subset of , let V be an open set in B such that , and let be an element of . There exists an open neighbourhood W of A such that , for a paracompact space is normal (TG, IX, p. 49, prop. 4). We shall prove that there exists an element of such that . Corollary 2 (I, p. 65) of prop. 6 then implies that the sheaf is soft.
Since the -space E is trivializable over , we may suppose that , where F is a topological space. The element of is then a -isomorphism of onto itself which induces the identical mapping of . Apply cor. 5 of IV, p. 439, to the spaces , , A = W, U = V, and Y = Z = F, to the mapping and to the identical mapping of . There therefore exists a -isomorphism of onto itself which induces the identical mapping of and which coincides with on , and a fortiori on . Hence the proposition.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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