Proposition 5
Tag 024K, permanent. Cite it as [Bourbaki, Tag 024K].
Topologie algébrique, chapter IV, § 6. Espaces classifiants
There exists a unique topology on compatible with its group structure for which the sets form a basis of neighbourhoods of the identity element.
Let us verify that the sets satisfy axioms (GV), (GV) and (GV) of TG, III, p. 4.
Let V be a neighbourhood of in G and let be a strictly positive real number. Let W be a neighbourhood of in G such that . Let and be elements of . If is such that , one has or . It follows that . Consequently, , which proves axiom (GV).
Let W be a neighbourhood of in G such that . Then , whence axiom (GV).
Let be an element of ; since the function takes only a finite number of values, there exists a neighbourhood W of in G such that for all . Let then be an element of . For , if V, then . Consequently, . This proves that , whence axiom (GV).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
Cited by
Nothing.
Cites
Nothing.