Bourbaki

Proposition 2

Tag 02HZ, permanent. Cite it as [Bourbaki, Tag 02HZ].

Théories spectrales, chapter II, § 1. Transformation de Fourier

Let n⩾0n\geqslant 0 be an integer and let G1,...,GnG_1, . . . ,G_n be locally compact commutative groups. Let G be the product group of the groups GjG_j for 1⩽j⩽n1\leqslant j\leqslant n. For 1⩽j⩽n1\leqslant j\leqslant n, let λj\lambda_j be the injection of GjG_j into G which associates to x∈Gjx\in G_j the element (xk)(x_k) such that xk=ex_k=e if k≠jk\not=j and xj=xx_j=x. The mapping

(λ^j)1⩽j⩽n:G^→∏1⩽j⩽nG^j (\widehat{\lambda}_j)_{1\leqslant j\leqslant n}:\widehat{G}\rightarrow \prod_{1\leqslant j\leqslant n}\widehat{G}_j

is a group isomorphism.

Let mm be the product mapping of G^n\widehat{G}^n into G^\widehat{G}, and for every jj such that 1⩽j⩽n1\leqslant j\leqslant n, let πj\pi_j be the projection of G onto GjG_j. Let μ\mu be the morphism of topological groups m∘(π^j)jm\circ (\widehat{\pi}_j)_j from ∏G^j\prod\widehat{G}_j into G^\widehat{G}, such that

⟨μ((χj)),(xj)⟩=∏j=1n⟨χj,xj⟩ \langle \mu((\chi_j)),(x_j)\rangle =\prod_{j=1}^n\langle \chi_j, x_j\rangle

The mapping μ\mu is continuous, and one verifies that μ\mu and (λ^j)(\widehat{\lambda}_j) are reciprocal bijections of one another. The proposition follows.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.