Bourbaki

Remark 1

Tag 02IK, permanent. Cite it as [Bourbaki, Tag 02IK].

Théories spectrales, chapter II, § 1. Transformation de Fourier

Certain formulas concerning the Fourier transform on L1(G)L^1(G) extend to the Fourier transform on L2(G)L^2(G). In particular, for f∈L2(G)f\in L^2(G) and χ∈G^\chi \in \widehat{G}, we have

F‾(f)=(χ↦F(f)(χ−1))=F(f‾)‾ \overline{\mathscr{F}}(f) = (\chi \mapsto \mathscr{F}(f)(\chi^{-1})) =\overline{\mathscr{F}(\overline{f})}
F(εx∗f)=η(x−1)F(f),F‾(εx∗f)=η(x)F(f) \mathscr{F}(\varepsilon_x*f) =\eta (x^{-1})\mathscr{F}(f),\overline{\mathscr{F}}(\varepsilon_x*f) =\eta (x)\mathscr{F}(f)
F(χf)=εχ∗F(f),F‾(χf)=εχ∗F(f) \mathscr{F}(\chi f) =\varepsilon_{\chi}*\mathscr{F}(f),\overline{\mathscr{F}}(\chi f) =\varepsilon_{\chi}*\mathscr{F}(f)

If σ\sigma is an automorphism of G and Δ the module of σ\sigma (INT, VII, §1, No.o4^o4, def. 4), then for f∈L2(G)f\in L^2(G), one has

F(f∘σ)=Δ−1F(f)∘σ^−1 \mathscr{F}(f\circ \sigma ) = \Delta^{-1}\mathscr{F}(f)\circ \widehat{\sigma}^{-1}

in L2(G)L^2(G).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.