Bourbaki

Proposition 10

Tag 02IM, permanent. Cite it as [Bourbaki, Tag 02IM].

Théories spectrales, chapter II, § 1. Transformation de Fourier

Let n⩾0n\geqslant 0 be an integer and let G1,⋯ ,GnG_1,\cdots ,G_n be locally compact commutative groups. Let μj\mu_j, for 1⩽j⩽n1\leqslant j\leqslant n, be Haar measures on GjG_j. Let G be the product group of the groups GjG_j for 1⩽j⩽n1\leqslant j\leqslant n. Let β\beta be the isomorphism of G^\widehat{G} onto ∏G^j\prod\widehat{G}_j of Prop. 2 of II, p. 206. The Haar measure on G^\widehat{G} dual to the product Haar measure μ=μ1⊗⋯⊗μn\mu=\mu_1\otimes \cdots \otimes \mu_n on G identifies with the product of the Haar measures μ^j\widehat{\mu}_j.

In fact, for every family (fj)(f_j) of non-zero elements of L2(Gj)\mathscr{L}^2(G_j), the function ff on G defined by (xj)↦∏fj(xj)(x_j)\mapsto \prod f_j(x_j) belong to L2(G)\mathscr{L}^2(G), and satisfies

∫G∣f∣2dμ=∏j∫Gj∣fj∣2dμj=∏j∫G^j∣FGj(f)∣2dμ^j \int_G|f|^2d\mu=\prod_j\int_{G_j}|f_j|^2d\mu_j=\prod_j\int_{\widehat{G}_j}|\mathscr{F}_{G_j}(f)|^2d\widehat{\mu}_j

by the Plancherel formula, which proves that the product Haar measure of the μ^j\widehat{\mu}_j identifies with the Haar measure dual to μ\mu.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.