Bourbaki

Proposition 19

Tag 02JS, permanent. Cite it as [Bourbaki, Tag 02JS].

Théories spectrales, chapter II, § 1. Transformation de Fourier

Let K be a locally compact non-discrete field, not necessarily commutative, and let G be the additive group of K, whose group law is denoted additively. Let χ\chi be a unitary character of G distinct from 1. For x,y∈Gx, y\in G, put θ(x,y)=χ(xy)\theta (x, y) =\chi (xy). Then G is in duality with itself relative to θ\theta.

For y∈Gy\in G, let χy\chi_y be the mapping of G into U\mathbf{U} such that χy(x)=\chi_y(x) = χ(xy)\chi (xy). We have χy∈G^\chi_y\in \widehat{G}, and it is necessary to prove that β:y↦χy\beta :y\mapsto \chi_y is an isomorphism of topological groups of G onto G^\widehat{G}.

The map β\beta is an injective homomorphism of G into G^\widehat{G}; it is continuous (TG, X, p. 28, Theorem 3 applied to the continuous map θ\theta of G×GG\times G into C\mathbf{C}). Let us prove that θ\theta is a homeomorphism onto its image. It is enough (Lemma 2 of II, p. 200) to prove that for every neighbourhood U of 0 in K, there exists a neighbourhood V of ee in G^\widehat{G} such that β−1(V)⊂U\overset{-1}{\beta}(V)\subset U. Let x↦∣x∣x\mapsto |x| be an absolute value on K defining the topology of K (AC, VI, §9, Noo1^o1, Proposition 1), and let x0∈Kx_0\in K be such that χ(x0)≠1\chi (x_0)\not= 1; let us set η=∣χ(x0)−1∣>0\eta =|\chi (x_0)-1|>0. Let U be a neighbourhood of 0 in K. There exists δ>0\delta >0 such that U contains the set of y∈Ky\in K such that ∣y∣<δ|y|< \delta. Let V be the set of characters ξ∈G^\xi \in \widehat{G} such that ∣⟨ξ,x⟩−1∣<η|\langle \xi , x\rangle -1|< \eta for every element x∈Kx\in K satisfying ∣x∣⩽∣x0∣/δ|x|\leqslant |x_0|/\delta. This is a neighbourhood of ee in G^\widehat{G}. If y≠0y\not= 0 is such that β(y)\beta (y) belongs to V, we therefore have ∣χ(xy)−1∣<∣χ(x0)−1∣|\chi (xy)-1|<|\chi (x_0)-1| for every xx such that ∣x∣⩽∣x0∣/δ|x|\leqslant |x_0|/\delta. Consequently, we have ∣x0y−1∣>∣x0∣/δ|x_0y^{-1}|>|x_0|/\delta, and therefore ∣y∣<δ|y|< \delta, so that y∈Uy\in U.

Since β\beta is a homeomorphism onto its image, the latter is closed in G^\widehat{G} (TG, III, p. 22, Corollary 2). But moreover the orthogonal of the image of β\beta is the set of elements xx of G such that χ(xy)=1\chi (xy) = 1 for all y∈Gy\in G, and is therefore reduced to {0}\{0\}. The image of β\beta is therefore dense in G^\widehat{G} (Corollary 3 of II, p. 228). We conclude that β\beta is surjective.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.