Bourbaki

Remark

Tag 02JX, permanent. Cite it as [Bourbaki, Tag 02JX].

Théories spectrales, chapter II, § 1. Transformation de Fourier

Given a subgroup H of Rn\mathbf{R}^n, there corresponds to it its orthogonal H⊥H^{\bot}, a subgroup of R^n=Rn\widehat{\mathbf{R}}^n=\mathbf{R}^n, which is none other than the subgroup associated with H defined in TG, VII, p. 6, no3^o3.

In the sequel, one will identify the dual of Rn\mathbf{R}^n (resp. of Tn\mathbf{T}^n) with Rn\mathbf{R}^n (resp. with Zn\mathbf{Z}^n) by the duality of the corollary. In particular, for f∈L1(Rn)f\in L^1(\mathbf{R}^n), its Fourier transform is identified with the function from Rn\mathbf{R}^n into C\mathbf{C} which to y∈Rny\in \mathbf{R}^n associates

F(f)(y)=∫Rnf(x)\mathscr{F}(f)(y) =\int_{\mathbf{R}^n}f(x) exp(−2iπx⋅y-2i\pi x\cdot y)dxdx.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.