Tag 02KD, permanent. Cite it as [Bourbaki, Tag 02KD].
Spectral Theories, II, p. 262
a) Let ω,p,q∈R with p⩽q. Put f(x)=eiωx for p⩽x⩽q, f(x)=0 for x>q or x<p. Then for y∈R, one has
F(f)(y)=iω−2πyeip(ω−2πy)−eiq(ω−2πy).
b) Let ω∈R,β>0. Put f(x)=e(−β+iω)x for x⩾0,f(x)=0 for x<0. Then for y∈R, one has
F(f)(y)=ω−2πy+iβi.
c) Let a>0. Put f(x)=a1e−a∣x∣ for x∈R. Then for y∈R, one has
F(f)(y)=4π2y2+a22.
d) Put f(x)=e−πx2 for x∈R. Then for y∈R, one has F(f)(y)=e−πy2. (Find a first-order linear differential equation satisfied
by the Fourier transform of f, and use the formula ∫0+∞e−t2dt=21π of FVR, VII, §1, No.o3.)
e) Let n∈N and let Q be a positive definite quadratic form on Rn. Let σ be a linear mapping on Rn such that Q(x)=∥σ(x)∥2. Let Q∗ be the positive definite quadratic form such that Q∗(y)=∥tσ−1(y)∥2 for every y∈Rn. Let z∈C be a complex number such that I(z)>0. The mapping f of Rn into C defined by f(x)= exp(iπzQ(x)) belongs to S(Rn) and one has
F(f)(y)=∣det(σ)∣−1(zi)n/2exp(iπz−1Q∗(y))
for every y∈Rn.
f) Let f∈C(R) be the function defined by f(x)= (sin(πx)/(πx))2 for x=0 and f(0)=1. We have F(f)(y)=0 if ∣y∣>1 and F(f)(y)=1−∣y∣ otherwise. Let g(x)=xf(x). We have F(g)(y)=0 if ∣y∣>1 and F(g)(y)= s(y)/(2iπ) otherwise.