Spectral Theories, II, p. 266
For every complex number s such that R(s)>1, put
ζ(s)=∑ns1
n⩾1 (“Riemann zeta function”).
a) The function ζ is holomorphic on the open subset of C formed by the complex numbers s such that R(s)>1.
b) For y∈R+∗, put
θ(y)=n∈Z∑e−πn2y
this series converges absolutely and uniformly on the compact subsets of R+∗. For every s such that R(s)>1, one has
π−s/2Γ(s/2)ζ(s)=21∫0+∞θ(y)ys/2ydy
(see FVR, VII, p. 10 for the gamma function in the complex plane).
c) For every y∈R+, one has θ(y ) = yθ(y). (Use the Poisson formula and exercise 1.)
d) For every s such that R(s)>1, one has
π−s/2Γ(s/2)ζ(s)=s(s−1)1+21∫1+∞(θ(y)−1)(ys/2+y(1−s)/2)dyy
e) There exists a unique holomorphic function on C−{1} whose restriction to the open set of complex numbers with real part >1 coincides with ζ. This function, still denoted by ζ, satisfies (s−1)ζ(s)→1 when s→1 (in other words, it has a simple pole of residue 1 at s=1).
f) The function Λ defined by
Λ(s)=π−s/2Γ(s/2)ζ(s)
is holomorphic on C−{0,1}; it has simple poles of residue 1 at s=0 and s=1. One has Λ(1−s)=Λ(s) for every s∈C−{0,1}.
g) Now prove that for every s∈C such that R(s)>1, one has
ζ(s)=p∏(1−p−s)−1
where the product is over the set of prime numbers and is absolutely convergent (“Euler product”).
h) When σ>1 tends to 1, one has
∑p−σ= log(σ−11)+O(1),
p
where the sum is over the prime numbers.
i) Every s∈C−{1} such that ζ(s)=0 is either of the form s=−2k, where k⩾1 is an integer, or satisfies 0⩽R(s)⩽1.
j) One has ζ(s)=0 if R(s)=1 and s=1. (Prove using the Euler product that
ζ(σ)3ζ(σ+it)4ζ(σ+2it)⩾1
for every σ>1 and t∈R, then consider t such that ζ(1+it)=0.)
Nothing.
Nothing.