Bourbaki

Exercise 20, § 1

Tag 02KW, permanent. Cite it as [Bourbaki, Tag 02KW].

Spectral Theories, II, p. 269

Soit n⩾1n\geqslant 1 un entier. We identify R+∗×Sn\mathbf{R}^*_+\times \mathbf{S}_n, and Rn+1−{0}\mathbf{R}^{n+1}-\{0\} by the mapping (t,z)↦tz(t, z)\mapsto tz. Let ω\omega be the unique measure on the sphere Sn⊂Rn+1\mathbf{S}_n\subset \mathbf{R}^{n+1} invariant under O(n+1,R)\mathbf{O}(n+ 1,\mathbf{R}) such that the measure tndt⊗μt^ndt\otimes \mu is identified with Lebesgue measure on Rn+1−{0}(\mathbf{R}^{n+1}-\{0\}(cf. INT, VII, p. 116, exercise 8). Let μ\mu denote the measure on Rn+1\mathbf{R}^{n+1} image of the measure ω\omega by the injection of Sn\mathbf{S}_n into Rn+1\mathbf{R}^{n+1}.

a) One has μ(Sn)=2π(n+1)/2Γ(n+12)−1(\mu(\mathbf{S}_n) = 2\pi^{(n+1)/2}\Gamma (\frac{n+1}{2})^{-1}(cf. INT, V, §8, no7)^o7).

b) For every real number k⩾0k\geqslant 0, define the function Jk:R+→CJ_k:\mathbf{R}_+\rightarrow \mathbf{C} by

Jk(t)=(t/2)kΓ(k+12)Γ(12)∫−11eiut(1−u2)k−1/2du J_k(t) =\frac{(t/2)^k}{\Gamma (k+\frac{1}{2})\Gamma (\frac{1}{2})}\int_{-1}^1e^{iut}(1-u^2)^{k-1/2}du

for t∈R+t\in \mathbf{R}_+ (« Bessel function of the first species »). For every x∈Rn+1x\in \mathbf{R}^{n+1}, one has

F(μ)(x)=2π∥x∥(n−1)/2J(n−1)/2(2π∥x∥) \mathscr{F}(\mu)(x) =\frac{2\pi}{\|x\|^{(n-1)/2}}J_{(n-1)/2}(2\pi \|x\|)

where ∥x∥\|x\| is the euclidean norm. c) If k∈Nk\in \mathbf{N}, one has

Jk(t)=12π∫02πJ_k(t) =\frac{1}{2\pi}\int_0^{2\pi} cos(tt sin(uu)−ku-ku)dudu

for every t∈R+t\in \mathbf{R}_+.

d) If nn is even, show that F(μ)(x)\mathscr{F}(\mu)(x) is a polynomial in ∥x∥±1/2\|x\|^{\pm 1/2}, cos(2π∥x∥\pi \|x\|) and sin(2π∥x∥\pi \|x\|); for n=2n= 2, one has

F(μ)(x)=\mathscr{F}(\mu)(x) = sin(22ππ∥x∥∥x∥2\pi \pi \|x\|\|x\|).

e) Let gg be a continuous function with compact support in R+∗\mathbf{R}_+^*. Put f(x)=f(x) = g(∥x∥2)∥x∥1−n/2g(\|x\|^2)\|x\|^{1-n/2} for every x∈Rnx\in \mathbf{R}^n. Then one has f^(y)=h(∥y∥2)∥y∥1−n/2\widehat{f}(y) =h(\|y\|^2)\|y\|^{1-n/2} for y∈Rny\in \mathbf{R}^n, where

∫+∞√ \int^{+\infty}\surd
h(s)=πg(t)Jn/2−1(2πts‾)dt h(s) =\pi g(t)J_{n/2-1}(2\pi \overline{ts})dt

for every s∈R+s\in \mathbf{R}_+ (« Hankel transform »).

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Machine translation of the English, by gpt-5-6. Not checked by a person.