Bourbaki

Exercise 26, § 1

Tag 02L2, permanent. Cite it as [Bourbaki, Tag 02L2].

Spectral Theories, II, p. 272

For every compact commutative group H, we denote by μH\mu_H the normalized Haar measure on H.

We suppose G compact. We denote by EGE_G the set of complex measures μ\mu on G such that the Fourier transform of μ\mu has integer values. It is a commutative subgroup of M1(G)\mathscr{M}^1(G) which contains the Haar measure μG\mu_G. We denote by FGF_G the subgroup of EGE_G generated by the measures x^iH(μH)\widehat{x} i_H(\mu_H), where H runs through the closed subgroups of G (iH(i_H denoting the canonical inclusion of H in G), and where x^\widehat{x} runs through G^\widehat{G}.

The purpose of this exercise is to prove that EG=FGE_G= F_G (« Cohen's idempotent theorem »).

a) Let φ:G1→G2\varphi : G_1\rightarrow G_2 be a morphism of compact commutative groups. The mapping μ↦φ(μ)\mu\mapsto \varphi (\mu) is a group homomorphism from EG1E_{G_1} into EG2E_{G_2}.

b) For every μ∈EG\mu\in E_G and every x^∈G^\widehat{x}\in \widehat{G}, one has x^μG∈EG\widehat{x}\mu_G\in E_G.

Let μ\mu be a complex measure on G. We denote by θ\theta the function on G such that μ=θ∣μ∣\mu=\theta |\mu|. We denote by Aμ⊂M1(G)A_\mu\subset \mathscr{M}^1(G) the set of measures of the form x^μ\widehat{x} \mu. Let ν\nu be an adherent point to AμA_\mu in M1(G)\mathscr{M}^1(G).

c) If ν\nu does not belong to AμA_\mu, then ν\nu is singular with respect to μG\mu_G.

d) Let ε>0\varepsilon >0. Let f∈C(G)f\in \mathscr{C}(G) of norm ⩽1\leqslant 1 such that ν(f)>(1−ε)∥μ∥\nu (f)>(1-\varepsilon )\|\mu\| and x^∈G^\widehat{x}\in \widehat{G} such that R(μ(x^f))>(1−ε)∥μ∥\mathscr{R}(\mu(\widehat{x} f))>(1-\varepsilon )\|\mu\|. Prove that

∫G∣1−fxθ^∣d∣μ∣⩽3ε1/2∥μ∥ \int_G|1-f\widehat{x\theta}|d|\mu|\leqslant 3\varepsilon^{1/2}\|\mu\|

e) Suppose that μ∈EG\mu\in E_G. Prove that ∥ν∥⩽∥μ∥−1/(36∥μ∥)\|\nu \|\leqslant \|\mu\|-1/(36\|\mu\|). (Apply the preceding question to two characters x^1\widehat{x}_1 and x^2\widehat{x}_2 such that x^1μ≠x^2μ\widehat{x}_1\mu\not=\widehat{x}_2\mu, and note that ∥x^1μ−x^2μ∥⩾1\|\widehat{x}_1\mu-\widehat{x}_2\mu\|\geqslant 1.) f) Conclude that EG=FGE_G= F_G and more precisely that every measure μ\mu in EGE_G is written

μ=∑k∈Knkx^ki(μHk) \mu=\sum_{k\in K}n_k\widehat{x}_ki(\mu_{H_k})

where the set K is finite, nk∈Z,x^k∈G^n_k\in \mathbf{Z},\widehat{x}_k\in \widehat{G}, and the measures i(μHk)i(\mu_{H_k}) are mutually singular. (Let μ∈EG\mu\in E_G; prove that there exists a measure ν≠0\nu \not= 0 in the closure of {ν∈Aμ∣ν(G)≠0}\{\nu \in A_\mu|\nu (G)\not= 0\} whose norm is minimal; then prove using e) that {x^∈G^∣ν(x^)≠0}\{\widehat{x}\in \widehat{G}|\nu (\widehat{x})\not= 0\} is finite, and apply the preceding exercise.)

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Machine translation of the English, by gpt-5-6. Not checked by a person.